促进C++中的ListalIa转换

促进LexicalCast在库“boost/lexical_cast.hpp”中定义,它提供了一个cast操作符boost::lexical_cast,可以将数字从字符串转换为int或double等数字类型,反之亦然。

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词法_cast是诸如 std::stoi() , std::stod() std::to_string() ,它们被添加到C++11中的标准库中。 现在让我们看看这个函数在程序中的实现。 例如:

Conversion
integer -> string
string- > integer
integer -> char
float- > string

相关例外情况: 如果转换失败,将抛出bad_词法_cast类型的异常,该异常派生自bad_cast。它抛出一个异常,因为float 52.50和字符串“geeksforgeks”无法转换为int类型的数字。

// CPP program to illustrate
// Boost.Lexical_Cast in C++
#include "boost/lexical_cast.hpp"
#include <bits/stdc++.h>
using namespace std;
using boost::lexical_cast;
using boost::bad_lexical_cast;
int main() {
// integer to string conversion
int s = 23;
string s1 = lexical_cast<string>(s);
cout << s1 << endl;
// integer to char conversion
array< char , 64> msg = lexical_cast<array< char , 64>>(45);
cout << msg[0] << msg[1] << endl;
// string to integer conversion in integer value
int num = lexical_cast< int >( "1234" );
cout << num << endl;
// bad conversion float to int
// using try and catch we display the error
try {
int num2 = lexical_cast< int >( "52.20" );
}
// To catch exception
catch (bad_lexical_cast &e) {
cout << "Exception caught : " << e.what() << endl;
}
// bad conversion string to integer character
// using tru and catch we display the error
try {
int i = lexical_cast< int >( "GeeksforGeeks" );
}
// catching Exception
catch (bad_lexical_cast &e) {
cout << "Exception caught :" << e.what() << endl;
}
return 0;
}


输出:-

23
45
1234
Exception caught : bad lexical cast: source type value could not be interpreted as target
Exception caught :bad lexical cast: source type value could not be interpreted as target

参考:- http://www.boost.org/

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