一年内寻找世纪的计划

给定一年,我们的任务是在给定的一年中找到世纪。第一个世纪从1到100开始,第二个世纪从101到200开始,以此类推。

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例如:

Input : year = 1970Output : 20 century Input : year = 1800Output : 18 century  

CPP

// C++ code for find the century
// in a given year
#include <bits/stdc++.h>
using namespace std;
void find_century( int year)
{
// No negative value is allow for year
if (year <= 0)
cout << "0 and negative is not allow"
<< "for a year" ;
// If year is between 1 to 100 it
// will come in 1st century
else if (year <= 100)
cout << "1st century" ;
else if (year % 100 == 0)
cout << year/ 100 << " century" ;
else
cout << year/ 100 + 1 << " century" ;
}
// Driven code
int main()
{
int year = 2001;
find_century(year);
return 0;
}


JAVA

// Java code for find the century
// in a given year
class GFG {
static void find_century( int year) {
// No negative value is allow for year
if (year <= 0 )
System.out.print( "0 and negative is not allow"
+ "for a year" );
// If year is between 1 to 100 it
// will come in 1st century
else if (year <= 100 )
System.out.print( "1st century" );
else if (year % 100 == 0 )
System.out.print(year / 100 + " century" );
else
System.out.print(year / 100 + 1 + " century" );
}
// Driver code
public static void main(String[] args) {
int year = 2001 ;
find_century(year);
}
}
// This code is contributed by Anant Agarwal.


Python3

# Python3 code for find the century
# in a given year
def find_century(year):
# No negative value is allow for year
if (year < = 0 ):
print ( "0 and negative is not allow for a year" )
# If year is between 1 to 100 it
# will come in 1st century
elif (year < = 100 ):
print ( "1st century" )
elif (year % 100 = = 0 ):
print (year / / 100 , "century" )
else :
print (year / / 100 + 1 , "century" )
# Driver code
year = 2001
find_century(year)
# This code is contributed by shubhamsingh10


C#

// C# code for find the century in a given year
using System;
class GFG {
static void find_century( int year) {
// No negative value is allow for year
if (year <= 0)
Console.WriteLine( "0 and negative is not"
+ " allow for a year" );
// If year is between 1 to 100 it
// will come in 1st century
else if (year <= 100)
Console.WriteLine( "1st century" );
else if (year % 100 == 0)
Console.WriteLine(year / 100 + " century" );
else
Console.WriteLine(year / 100 + 1 +
" century" );
}
// Driver code
public static void Main() {
int year = 2001;
find_century(year);
}
}
// This code is contributed by vt_m.


PHP

<?php
// PHP code for find the century
// in a given year
function find_century( $year )
{
// No negative value is
// allow for year
if ( $year <= 0)
echo "0 and negative is not allow"
, "for a year" ;
// If year is between 1 to 100 it
// will come in 1st century
else if ( $year <= 100)
echo "1st century" ;
else if ( $year % 100 == 0)
echo $year / 100 , " century" ;
else
echo floor ( $year / 100) + 1
, " century" ;
}
// Driver Code
$year = 2001;
find_century( $year );
// This code is contributed by anuj_67.
?>


Javascript

<script>
// Java Script code for find the century
// in a given year
function find_century( year) {
// No negative value is allow for year
if (year <= 0)
document.write( "0 and negative is not allow"
+ "for a year" );
// If year is between 1 to 100 it
// will come in 1st century
else if (year <= 100)
document.write( "1st century" );
else if (year % 100 == 0)
document.write(parseInt(year / 100) + " century" );
else
document.write(parseInt(year / 100) + 1 + " century" );
}
// Driver code
let year = 2001;
find_century(year);
//contributed by sravan kumar
</script>


输出:

21 century

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