给定一年,我们的任务是在给定的一年中找到世纪。第一个世纪从1到100开始,第二个世纪从101到200开始,以此类推。
null
例如:
Input : year = 1970Output : 20 century Input : year = 1800Output : 18 century
CPP
// C++ code for find the century // in a given year #include <bits/stdc++.h> using namespace std; void find_century( int year) { // No negative value is allow for year if (year <= 0) cout << "0 and negative is not allow" << "for a year" ; // If year is between 1 to 100 it // will come in 1st century else if (year <= 100) cout << "1st century" ; else if (year % 100 == 0) cout << year/ 100 << " century" ; else cout << year/ 100 + 1 << " century" ; } // Driven code int main() { int year = 2001; find_century(year); return 0; } |
JAVA
// Java code for find the century // in a given year class GFG { static void find_century( int year) { // No negative value is allow for year if (year <= 0 ) System.out.print( "0 and negative is not allow" + "for a year" ); // If year is between 1 to 100 it // will come in 1st century else if (year <= 100 ) System.out.print( "1st century" ); else if (year % 100 == 0 ) System.out.print(year / 100 + " century" ); else System.out.print(year / 100 + 1 + " century" ); } // Driver code public static void main(String[] args) { int year = 2001 ; find_century(year); } } // This code is contributed by Anant Agarwal. |
Python3
# Python3 code for find the century # in a given year def find_century(year): # No negative value is allow for year if (year < = 0 ): print ( "0 and negative is not allow for a year" ) # If year is between 1 to 100 it # will come in 1st century elif (year < = 100 ): print ( "1st century" ) elif (year % 100 = = 0 ): print (year / / 100 , "century" ) else : print (year / / 100 + 1 , "century" ) # Driver code year = 2001 find_century(year) # This code is contributed by shubhamsingh10 |
C#
// C# code for find the century in a given year using System; class GFG { static void find_century( int year) { // No negative value is allow for year if (year <= 0) Console.WriteLine( "0 and negative is not" + " allow for a year" ); // If year is between 1 to 100 it // will come in 1st century else if (year <= 100) Console.WriteLine( "1st century" ); else if (year % 100 == 0) Console.WriteLine(year / 100 + " century" ); else Console.WriteLine(year / 100 + 1 + " century" ); } // Driver code public static void Main() { int year = 2001; find_century(year); } } // This code is contributed by vt_m. |
PHP
<?php // PHP code for find the century // in a given year function find_century( $year ) { // No negative value is // allow for year if ( $year <= 0) echo "0 and negative is not allow" , "for a year" ; // If year is between 1 to 100 it // will come in 1st century else if ( $year <= 100) echo "1st century" ; else if ( $year % 100 == 0) echo $year / 100 , " century" ; else echo floor ( $year / 100) + 1 , " century" ; } // Driver Code $year = 2001; find_century( $year ); // This code is contributed by anuj_67. ?> |
Javascript
<script> // Java Script code for find the century // in a given year function find_century( year) { // No negative value is allow for year if (year <= 0) document.write( "0 and negative is not allow" + "for a year" ); // If year is between 1 to 100 it // will come in 1st century else if (year <= 100) document.write( "1st century" ); else if (year % 100 == 0) document.write(parseInt(year / 100) + " century" ); else document.write(parseInt(year / 100) + 1 + " century" ); } // Driver code let year = 2001; find_century(year); //contributed by sravan kumar </script> |
输出:
21 century
© 版权声明
文章版权归作者所有,未经允许请勿转载。
THE END