本文旨在给出一种模式打印的C++实现。
null
简单金字塔图案
CPP
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart( int n) { // Outer loop to handle number of rows // n in this case for ( int i = 0; i < n; i++) { // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j <= i; j++) { // Printing stars cout << "* " ; } // Ending line after each row cout << endl; } } // Driver Function int main() { int n = 5; pypart(n); return 0; } |
输出
* * * * * * * * * * * * * * *
使用while循环打印上面的图案
CPP
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart( int n) { // Outer loop to handle number of rows // n in this case int i = 0, j = 0; while (i < n) { // Inner loop to handle number of columns // values changing acc. to outer loop while (j <= i) { // Printing stars cout << "* " ; j++; } j = 0; // we have to reset j value so as it can // start from beginning and print * equal to i. i++; // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; pypart(n); return 0; } |
输出
* * * * * * * * * * * * * * *
180度旋转后
CPP
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Driver Code int main() { int n = 5; //looping rows for ( int i=n; i>0; i--) { for ( int j=0; j<=n; j++) //looping columns { if (j>=i) { cout<< "*" ; } else { cout<< " " ; } } cout<<endl; } return 0; } |
输出
* * * * * * * * * * * * * * *
使用while循环打印上面的图案
CPP
// C++ code to demonstrate pattern printing #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart2( int n) { int i = 0, j = 0, k = 0; while (i < n) { // for number of spaces while (k < (n - i - 1)) { cout << " " ; k++; } // resetting k because we want to run k from // beginning. k = 0; while (j <= i) { cout << "* " ; j++; } // resetting k so as it can start from 0. j = 0; i++; cout << endl; } } // Driver Code int main() { int n = 5; // Function Call pypart2(n); return 0; } |
输出
* * * * * * * * * * * * * * *
倒金字塔图案
C++
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart( int n) { // Outer loop to handle number of rows // n in this case for ( int i = n; i > 0; i--) { // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j < i; j++) { // Printing stars cout << "* " ; } // Ending line after each row cout << endl; } } // Driver Function int main() { int n = 5; pypart(n); return 0; } |
输出
* * * * * * * * * * * * * * *
使用while循环打印上面的图案
C++
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart( int n) { // Outer loop to handle number of rows // n in this case int i = n, j = 0; while (i > 0) { // Inner loop to handle number of columns // values changing acc. to outer loop while (j < i) { // Printing stars cout << "* " ; j++; } j = 0; // we have to reset j value so as it can // start from beginning and print * equal to i. i--; // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; pypart(n); return 0; } |
输出
* * * * * * * * * * * * * * *
180度旋转后
C++
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart2( int n) { // number of spaces int k = 2 * n - 2; // Outer loop to handle number of rows // n in this case for ( int i = n; i > 0; i--) { // Inner loop to handle number spaces // values changing acc. to requirement for ( int j = 0; j < n-i; j++) cout << " " ; // Decrementing k after each loop k = k - 2; // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j < i; j++) { // Printing stars cout << "* " ; } // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call pypart2(n); return 0; } |
输出
* * * * * * * * * * * * * * *
使用while循环打印上面的图案
C++
// C++ code to demonstrate pattern printing #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart2( int n) { int i = n, j = 0, k = 0; while (i > 0) { // for number of spaces while (k < (n - i)) { cout << " " ; k++; } // resetting k because we want to run k from // beginning. k = 0; while (j < i) { cout << "* " ; j++; } // resetting k so as it can start from 0. j = 0; i--; cout << endl; } } // Driver Code int main() { int n = 5; // Function Call pypart2(n); return 0; } |
输出
* * * * * * * * * * * * * * *
打印三角形
方法1
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void triangle( int n) { // number of spaces int k = 2 * n - 2; // Outer loop to handle number of rows // n in this case for ( int i = 0; i < n; i++) { // Inner loop to handle number spaces // values changing acc. to requirement for ( int j = 0; j < k; j++) cout << " " ; // Decrementing k after each loop k = k - 1; // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j <= i; j++) { // Printing stars cout << "* " ; } // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call triangle(n); return 0; } |
方法2
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart2( int n) { // Number of spaces int i, j, k = n; // Outer loop to handle number of rows // n in this case for (i = 1; i <= n; i++) { // Inner loop for columns for (j = 1; j <= n; j++) { // Condition to print star pattern if (j >= k) cout << "* " ; else cout << " " ; } k--; cout << "" ; } } // Driver Code int main() { int n = 5; // Function Call pypart2(n); return 0; } |
输出
* * * * * * * * * * * * * * *
方法3
// C++ code to demonstrate star pattern #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart2( int n) { int i = 0, j = 0, k = 0; while (i < n) { // for spacing while (k <= n - i - 2) { cout << " " ; k++; } k = 0; // For Pattern printing while (j < 2 * i - 1) { cout << "*" ; j++; } j = 0; i++; cout << endl; } } // Driver Code int main() { int n = 5; // Function Call pypart2(n); return 0; } |
输出
* *** ************
数字模式
CPP
// C++ code to demonstrate printing // pattern of numbers #include <iostream> using namespace std; // Function to demonstrate printing // pattern void numpat( int n) { // initializing starting number int num = 1; // Outer loop to handle number of rows // n in this case for ( int i = 0; i < n; i++) { // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j <= i; j++) cout << num << " " ; // Incrementing number at each column num = num + 1; // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call numpat(n); return 0; } |
输出
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
上面的模式使用while循环
CPP
// C++ Code for pattern Printing #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart( int n) { int i = 1, j = 0; while (i <= n) { while (j <= i - 1) { cout << i << " " ; j++; } j = 0; i++; cout << endl; } } // Driver Code int main() { int n = 5; // Function Call pypart(n); return 0; } |
输出
1 2 2 3 3 3 4 4 4 4 5 5 5 5 5
没有重新分配的数字
CPP
// C++ code to demonstrate printing pattern of numbers #include <iostream> using namespace std; // Function to demonstrate printing pattern void numpat( int n) { // Initialising starting number int num = 1; // Outer loop to handle number of rows // n in this case for ( int i = 0; i < n; i++) { // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j <= i; j++) { // Printing number cout << num << " " ; // Incrementing number at each column num = num + 1; } // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call numpat(n); return 0; } |
输出
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
上面的模式使用while循环
CPP
// C++ code to demonstrate printing pattern of numbers #include <iostream> using namespace std; // Function to demonstrate printing pattern void pypart( int n) { int i = 1, j = 0; // here we declare an num variable which is // assigned value 1 int num = 1; while (i <= n) { while (j <= i - 1) { // Printing numbers cout << num << " " ; // here we are increasing num for every // iteration. num++; j++; } j = 0; i++; // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call pypart(n); return 0; } |
输出
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
字符模式
CPP
// C++ code to demonstrate printing pattern of alphabets #include <iostream> using namespace std; // Function to demonstrate printing pattern void alphabet( int n) { // Initializing value corresponding to 'A' // ASCII value int num = 65; // Outer loop to handle number of rows // n in this case for ( int i = 0; i < n; i++) { // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j <= i; j++) { // Explicitly converting to char char ch = char (num); // Printing char value cout << ch << " " ; } // Incrementing number num = num + 1; // Ending line after each row cout << endl; } } // Driver Function int main() { int n = 5; alphabet(n); return 0; } |
输出
A B B C C C D D D D E E E E E
上面的模式使用while循环
CPP
// C++ code to demonstrate printing pattern of alphabets #include <iostream> using namespace std; // Function to demonstrate printing pattern void alphabet( int n) { int i = 1, j = 0; // assigning ASCII value of A which is 65 int num = 65; // converting ASCII value to character, // now our alpha variable is having // value A after typecasting. char alpha = char (num); while (i <= n) { // alpha is having A value and it // will change as soon as alpha // increased or decreased. while (j <= i - 1) { cout << alpha << " " ; j++; } // incrementing alpha value so as it can // point to next character alpha++; // we have to reset j value so as it can // start from beginning and print * equal to // i. j = 0; i++; // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call alphabet(n); return 0; } |
输出
A B B C C C D D D D E E E E E
连续字符模式
CPP
// C++ code to demonstrate printing pattern of alphabets #include <iostream> using namespace std; // Function to demonstrate printing pattern void contalpha( int n) { // Initializing value corresponding to 'A' // ASCII value int num = 65; // Outer loop to handle number of rows // n in this case for ( int i = 0; i < n; i++) { // Inner loop to handle number of columns // values changing acc. to outer loop for ( int j = 0; j <= i; j++) { // Explicitly converting to char char ch = char (num); // Printing char value cout << ch << " " ; // Incrementing number at each column num = num + 1; } // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call contalpha(n); return 0; } |
输出
A B C D E F G H I J K L M N O
上面的模式使用while循环
CPP
// C++ code to demonstrate printing pattern of alphabets #include <iostream> using namespace std; // Function to demonstrate printing pattern void contalpha( int n) { int i = 1, j = 0; int num = 65; char alpha = char (num); while (i <= n) { while (j <= i - 1) { cout << alpha << " " ; // incrementing alpha value in every // iteration so as it can assign to // next character alpha++; j++; } j = 0; i++; // Ending line after each row cout << endl; } } // Driver Code int main() { int n = 5; // Function Call contalpha(n); return 0; } |
输出
A B C D E F G H I J K L M N O
下面的文章将讨论python语言的打印模式： 用Python打印金字塔图案的程序 本文由 曼吉特·辛格（S.Nandini） .如果你喜欢GeekSforgek，并想贡献自己的力量，你也可以使用 写极客。组织 或者把你的文章寄去评论-team@geeksforgeeks.org.看到你的文章出现在Geeksforgeks主页上，并帮助其他极客。 如果您发现任何不正确的地方，或者您想分享有关上述主题的更多信息，请写下评论。
© 版权声明
文章版权归作者所有，未经允许请勿转载。
THE END
![关于”PostgreSQL错误：关系[表]不存在“问题的原因和解决方案-yiteyi-C++库](https://www.yiteyi.com/wp-content/themes/zibll/img/thumbnail.svg)
