可以使用simple for循环在python中打印图案。 第一外环 用来处理 行数 和 内嵌套循环 用于处理 列数 .通过操纵打印语句，可以打印不同的数字模式、字母模式或星形模式。 本文展示了其中一些模式。
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- 简单金字塔图案
Python3
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern def pypart(n): # outer loop to handle number of rows # n in this case for i in range ( 0 , n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # printing stars print ( "* " ,end = "") # ending line after each row print ( " ) # Driver Code n = 5 pypart(n) |
输出
* * * * * * * * * * * * * * *
- 另一种方法： 使用Python3中的List，可以以更简单的方式完成
python
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern def pypart(n): myList = [] for i in range ( 1 ,n + 1 ): myList.append( "*" * i) print ( "" .join(myList)) # Driver Code n = 5 pypart(n) |
输出
***************
- 180度旋转后
Python3
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern def pypart2(n): # number of spaces k = 2 * n - 2 # outer loop to handle number of rows for i in range ( 0 , n): # inner loop to handle number spaces # values changing acc. to requirement for j in range ( 0 , k): print (end = " " ) # decrementing k after each loop k = k - 2 # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # printing stars print ( "* " , end = "") # ending line after each row print ( " ) # Driver Code n = 5 pypart2(n) |
输出
* * * * * * * * * * * * * * *
- 打印三角形
Python3
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern triangle def triangle(n): # number of spaces k = n - 1 # outer loop to handle number of rows for i in range ( 0 , n): # inner loop to handle number spaces # values changing acc. to requirement for j in range ( 0 , k): print (end = " " ) # decrementing k after each loop k = k - 1 # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # printing stars print ( "* " , end = "") # ending line after each row print ( " ) # Driver Code n = 5 triangle(n) |
输出
* * * * * * * * * * * * * * *
- 数字模式
Python3
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern of numbers def numpat(n): # initialising starting number num = 1 # outer loop to handle number of rows for i in range ( 0 , n): # re assigning num num = 1 # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # printing number print (num, end = " " ) # incrementing number at each column num = num + 1 # ending line after each row print ( " ) # Driver code n = 5 numpat(n) |
输出
1 1 2 1 2 3 1 2 3 4 1 2 3 4 5
- 没有重新分配的数字
Python3
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern of numbers def contnum(n): # initializing starting number num = 1 # outer loop to handle number of rows for i in range ( 0 , n): # not re assigning num # num = 1 # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # printing number print (num, end = " " ) # incrementing number at each column num = num + 1 # ending line after each row print ( " ) n = 5 # sending 5 as argument # calling Function contnum(n) |
输出
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
- 字符模式
Python3
# Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern of alphabets def alphapat(n): # initializing value corresponding to 'A' # ASCII value num = 65 # outer loop to handle number of rows # 5 in this case for i in range ( 0 , n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # explicitly converting to char ch = chr (num) # printing char value print (ch, end = " " ) # incrementing number num = num + 1 # ending line after each row print ( " ) # Driver Code n = 5 alphapat(n) |
输出
A B B C C C D D D D E E E E E
- 连续字符模式
Python3
# Python code 3.x to demonstrate star pattern # Function to demonstrate printing pattern of alphabets def contalpha(n): # initializing value corresponding to 'A' # ASCII value num = 65 # outer loop to handle number of rows - for i in range ( 0 , n): # inner loop to handle number of columns # values changing acc. to outer loop for j in range ( 0 , i + 1 ): # explicitly converting to char ch = chr (num) # printing char value print (ch, end = " " ) # incrementing at each column num = num + 1 # ending line after each row print ( " ) # Driver code n = 5 contalpha(n) |
- 输出：
A B C D E F G H I J K L M N O
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