将一个大小为n的数组合并到另一个大小为m+n的数组中

有两个排序数组。第一个是m+n大小的,只包含m个元素。另一个大小为n,包含n个元素。将这两个数组合并到第一个大小为m+n的数组中,以便对输出进行排序。 输入:带有m+n个元素的数组(mPlusN[])。

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MergemPlusN

NA=>数组mPlusN[]中的值未填充/不可用。应该有n个这样的数组块。 输入:包含n个元素的数组(n[])。

MergeN

输出:N[]合并到mPlusN[](修改后的mPlusN[])

MergemPlusN_Res

算法:

Let first array be mPlusN[] and other array be N[]1) Move m elements of mPlusN[] to end.2) Start from nth element of mPlusN[] and 0th    element of N[] and merge them into mPlusN[].

以下是上述算法的实现:

C++

// C++ program to Merge an array of
// size n into another array of size m + n
#include <bits/stdc++.h>
using namespace std;
/* Assuming -1 is filled for the places
where element is not available */
#define NA -1
/* Function to move m elements at
the end of array mPlusN[] */
void moveToEnd( int mPlusN[], int size)
{
int j = size - 1;
for ( int i = size - 1; i >= 0; i--)
if (mPlusN[i] != NA)
{
mPlusN[j] = mPlusN[i];
j--;
}
}
/* Merges array N[] of size n into
array mPlusN[] of size m+n*/
int merge( int mPlusN[], int N[], int m, int n)
{
int i = n; /* Current index of i/p part of mPlusN[]*/
int j = 0; /* Current index of N[]*/
int k = 0; /* Current index of output mPlusN[]*/
while (k < (m + n))
{
/* Take an element from mPlusN[] if
a) value of the picked element is smaller
and we have not reached end of it
b) We have reached end of N[] */
if ((j == n)||(i < (m + n) && mPlusN[i] <= N[j]))
{
mPlusN[k] = mPlusN[i];
k++;
i++;
}
else // Otherwise take element from N[]
{
mPlusN[k] = N[j];
k++;
j++;
}
}
}
/* Utility that prints out an array on a line */
void printArray( int arr[], int size)
{
for ( int i = 0; i < size; i++)
cout << arr[i] << " " ;
cout << endl;
}
/* Driver code */
int main()
{
/* Initialize arrays */
int mPlusN[] = {2, 8, NA, NA, NA, 13, NA, 15, 20};
int N[] = {5, 7, 9, 25};
int n = sizeof (N) / sizeof (N[0]);
int m = sizeof (mPlusN) / sizeof (mPlusN[0]) - n;
/*Move the m elements at the end of mPlusN*/
moveToEnd(mPlusN, m + n);
/*Merge N[] into mPlusN[] */
merge(mPlusN, N, m, n);
/* Print the resultant mPlusN */
printArray(mPlusN, m+n);
return 0;
}


C

// C program to Merge an array of
// size n into another array of size m + n
#include <stdio.h>
/* Assuming -1 is filled for
the places where element
is not available */
#define NA -1
/* Function to move m elements
at the end of array mPlusN[]
*/
void moveToEnd( int mPlusN[], int size)
{
int i = 0, j = size - 1;
for (i = size - 1; i >= 0; i--)
if (mPlusN[i] != NA) {
mPlusN[j] = mPlusN[i];
j--;
}
}
/* Merges array N[] of size n into array mPlusN[]
of size m+n*/
int merge( int mPlusN[], int N[], int m, int n)
{
int i = n; /* Current index of i/p part of mPlusN[]*/
int j = 0; /* Current index of N[]*/
int k = 0; /* Current index of output mPlusN[]*/
while (k < (m + n))
{
/* Take an element from mPlusN[] if
a) value of the picked element is smaller and we
have not reached end of it
b) We have reached end of N[] */
if ((j == n)|| (i < (m + n)
&& mPlusN[i] <= N[j]))
{
mPlusN[k] = mPlusN[i];
k++;
i++;
}
else // Otherwise take element from N[]
{
mPlusN[k] = N[j];
k++;
j++;
}
}
}
/* Utility that prints out an array on a line */
void printArray( int arr[], int size)
{
int i;
for (i = 0; i < size; i++)
printf ( "%d " , arr[i]);
printf ( "" );
}
/* Driver code */
int main()
{
/* Initialize arrays */
int mPlusN[] = { 2, 8, NA, NA, NA, 13, NA, 15, 20 };
int N[] = { 5, 7, 9, 25 };
int n = sizeof (N) / sizeof (N[0]);
int m = sizeof (mPlusN) / sizeof (mPlusN[0]) - n;
/*Move the m elements at the end of mPlusN*/
moveToEnd(mPlusN, m + n);
/*Merge N[] into mPlusN[] */
merge(mPlusN, N, m, n);
/* Print the resultant mPlusN */
printArray(mPlusN, m + n);
return 0;
}


JAVA

// Java program to Merge an array of
// size n into another array of size m + n
class MergeArrays {
/* Function to move m
elements at the end of array
* mPlusN[] */
void moveToEnd( int mPlusN[], int size)
{
int i, j = size - 1 ;
for (i = size - 1 ; i >= 0 ; i--) {
if (mPlusN[i] != - 1 ) {
mPlusN[j] = mPlusN[i];
j--;
}
}
}
/* Merges array N[] of
size n into array mPlusN[]
of size m+n*/
void merge( int mPlusN[], int N[], int m, int n)
{
int i = n;
/* Current index of i/p part of mPlusN[]*/
int j = 0 ;
/* Current index of N[]*/
int k = 0 ;
/* Current index of output mPlusN[]*/
while (k < (m + n))
{
/* Take an element from mPlusN[] if
a) value of the picked element is smaller and we
have not reached end of it b) We have reached
end of N[] */
if ((i < (m + n) && mPlusN[i] <= N[j])
|| (j == n)) {
mPlusN[k] = mPlusN[i];
k++;
i++;
}
else // Otherwise take element from N[]
{
mPlusN[k] = N[j];
k++;
j++;
}
}
}
/* Utility that prints out an array on a line */
void printArray( int arr[], int size)
{
int i;
for (i = 0 ; i < size; i++)
System.out.print(arr[i] + " " );
System.out.println( "" );
}
// Driver Code
public static void main(String[] args)
{
MergeArrays mergearray = new MergeArrays();
/* Initialize arrays */
int mPlusN[] = { 2 , 8 , - 1 , - 1 , - 1 , 13 , - 1 , 15 , 20 };
int N[] = { 5 , 7 , 9 , 25 };
int n = N.length;
int m = mPlusN.length - n;
/*Move the m elements at the end of mPlusN*/
mergearray.moveToEnd(mPlusN, m + n);
/*Merge N[] into mPlusN[] */
mergearray.merge(mPlusN, N, m, n);
/* Print the resultant mPlusN */
mergearray.printArray(mPlusN, m + n);
}
}
// This code has been contributed by Mayank Jaiswal


蟒蛇3

# Python program to Merge an array of
# size n into another array of size m + n
NA = - 1
# Function to move m elements
# at the end of array mPlusN[]
def moveToEnd(mPlusN, size):
i = 0
j = size - 1
for i in range (size - 1 , - 1 , - 1 ):
if (mPlusN[i] ! = NA):
mPlusN[j] = mPlusN[i]
j - = 1
# Merges array N[]
# of size n into array mPlusN[]
# of size m+n
def merge(mPlusN, N, m, n):
i = n # Current index of i/p part of mPlusN[]
j = 0 # Current index of N[]
k = 0 # Current index of output mPlusN[]
while (k < (m + n)):
# Take an element from mPlusN[] if
# a) value of the picked
# element is smaller and we have
# not reached end of it
# b) We have reached end of N[] */
if ((j = = n) or (i < (m + n) and mPlusN[i] < = N[j])):
mPlusN[k] = mPlusN[i]
k + = 1
i + = 1
else : # Otherwise take element from N[]
mPlusN[k] = N[j]
k + = 1
j + = 1
# Utility that prints
# out an array on a line
def printArray(arr, size):
for i in range (size):
print (arr[i], " " , end = "")
print ()
# Driver function to
# test above functions
# Initialize arrays
mPlusN = [ 2 , 8 , NA, NA, NA, 13 , NA, 15 , 20 ]
N = [ 5 , 7 , 9 , 25 ]
n = len (N)
m = len (mPlusN) - n
# Move the m elements
# at the end of mPlusN
moveToEnd(mPlusN, m + n)
# Merge N[] into mPlusN[]
merge(mPlusN, N, m, n)
# Print the resultant mPlusN
printArray(mPlusN, m + n)
# This code is contributed
# by Anant Agarwal.


C#

// C# program to Merge an array of
// size n into another array of size m + n
using System;
class GFG {
/* Function to move m elements at
the end of array mPlusN[] */
public virtual void moveToEnd( int [] mPlusN, int size)
{
int i, j = size - 1;
for (i = size - 1; i >= 0; i--)
{
if (mPlusN[i] != -1) {
mPlusN[j] = mPlusN[i];
j--;
}
}
}
/* Merges array N[] of size n
into array mPlusN[] of size m+n*/
public virtual void merge( int [] mPlusN,
int [] N, int m,
int n)
{
int i = n;
/* Current index of i/p
part of mPlusN[]*/
int j = 0;
/* Current index of N[]*/
int k = 0;
/* Current index of output mPlusN[]*/
while (k < (m + n))
{
/* Take an element from mPlusN[] if
a) value of the picked element is smaller
and we have not reached end of it
b) We have reached end of N[] */
if ((j == n)(i < (m + n)
&& mPlusN[i] <= N[j]))
{
mPlusN[k] = mPlusN[i];
k++;
i++;
}
else // Otherwise take element from N[]
{
mPlusN[k] = N[j];
k++;
j++;
}
}
}
/* Utility that prints out
an array on a line */
public virtual void printArray( int [] arr, int size)
{
int i;
for (i = 0; i < size; i++) {
Console.Write(arr[i] + " " );
}
Console.WriteLine( "" );
}
// Driver Code
public static void Main( string [] args)
{
GFG mergearray = new GFG();
/* Initialize arrays */
int [] mPlusN = new int [] { 2,  8,  -1, -1, -1,
13, -1, 15, 20 };
int [] N = new int [] { 5, 7, 9, 25 };
int n = N.Length;
int m = mPlusN.Length - n;
/*Move the m elements at the
end of mPlusN*/
mergearray.moveToEnd(mPlusN, m + n);
/*Merge N[] into mPlusN[] */
mergearray.merge(mPlusN, N, m, n);
/* Print the resultant mPlusN */
mergearray.printArray(mPlusN, m + n);
}
}
// This code is contributed by Shrikant13


PHP

<?php
// PHP program to Merge an array
// of size n into another array
// of size m + n
/* Assuming -1 is filled for
the places where element is
not available */
$NA = -1;
/* Function to move m elements
at the end of array mPlusN[] */
function moveToEnd(& $mPlusN , $size )
{
global $NA ;
$j = $size - 1;
for ( $i = $size - 1; $i >= 0; $i --)
if ( $mPlusN [ $i ] != $NA )
{
$mPlusN [ $j ] = $mPlusN [ $i ];
$j --;
}
}
/* Merges array N[] of size n
into array mPlusN[] of size m+n*/
function merge(& $mPlusN , & $N , $m , $n )
{
$i = $n ; /* Current index of i/p
part of mPlusN[]*/
$j = 0; /* Current index of N[]*/
$k = 0; /* Current index of
output mPlusN[]*/
while ( $k < ( $m + $n ))
{
/* Take an element from mPlusN[] if
a) value of the picked element
is smaller and we have not
reached end of it
b) We have reached end of N[] */
if (( $j == $n ) || ( $i < ( $m + $n ) &&
$mPlusN [ $i ] <= $N [ $j ]))
{
$mPlusN [ $k ] = $mPlusN [ $i ];
$k ++;
$i ++;
}
else // Otherwise take element from N[]
{
$mPlusN [ $k ] = $N [ $j ];
$k ++;
$j ++;
}
}
}
/* Utility that prints out
an array on a line */
function printArray(& $arr , $size )
{
for ( $i = 0; $i < $size ; $i ++)
echo $arr [ $i ] . " " ;
echo "" ;
}
// Driver Code
/* Initialize arrays */
$mPlusN = array (2, 8, $NA , $NA , $NA ,
13, $NA , 15, 20);
$N = array (5, 7, 9, 25);
$n = sizeof( $N );
$m = sizeof( $mPlusN ) - $n ;
/* Move the m elements
at the end of mPlusN*/
moveToEnd( $mPlusN , $m + $n );
/* Merge N[] into mPlusN[] */
merge( $mPlusN , $N , $m , $n );
/* Print the resultant mPlusN */
printArray( $mPlusN , $m + $n );
// This code is contributed
// by ChitraNayal
?>


Javascript

<script>
// Javascript program to Merge an array of
// size n into another array of size m + n
/* Function to move m
elements at the end of array
* mPlusN[] */
function moveToEnd(mPlusN,size)
{
let i = 0;
let j = size - 1;
for (i = size - 1; i >= 0; i--)
{
if (mPlusN[i] != -1)
{
mPlusN[j] = mPlusN[i];
j--;
}
}
}
/* Merges array N[] of
size n into array mPlusN[]
of size m+n*/
function merge(mPlusN, N, m, n)
{
let i = n;
/* Current index of i/p part of mPlusN[]*/
let j = 0;
/* Current index of N[]*/
let k = 0;
/* Current index of output mPlusN[]*/
while (k < (m + n))
{
/* Take an element from mPlusN[] if
a) value of the picked element is smaller and we
have not reached end of it b) We have reached
end of N[] */
if ((i < (m + n) && mPlusN[i] <= N[j]) || (j == n))
{
mPlusN[k] = mPlusN[i];
k++;
i++;
}
else // Otherwise take element from N[]
{
mPlusN[k] = N[j];
k++;
j++;
}
}
}
/* Utility that prints out an array on a line */
function printArray(arr,size)
{
let i = 0;
for (i = 0; i < size; i++)
{
document.write(arr[i] + " " );
}
document.write( "" );
}
// Driver Code
/* Initialize arrays */
let mPlusN = [2, 8, -1, -1, -1, 13, -1, 15, 20];
let N = [ 5, 7, 9, 25]
let n = N.length;
let m = mPlusN.length - n;
/*Move the m elements at the end of mPlusN*/
moveToEnd(mPlusN, m + n);
/*Merge N[] into mPlusN[] */
merge(mPlusN, N, m, n);
/* Print the resultant mPlusN */
printArray(mPlusN, m + n);
// This code is contributed by avanitrachhadiya2155
</script>


输出

2 5 7 8 9 13 15 20 25 

时间复杂性: O(m+n)

如果您在上述程序中发现任何错误,或者找到更好的方法来解决相同的问题,请写下评论。

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