检查数字是否在给定的基数内

// CPP program to check if given

// number is in given base or not.

#include <cstring>

#include <iostream>

using namespace std;

bool isInGivenBase(string str, int base)

{

// Allowed bases are till 16 (Hexadecimal)

if (base > 16)

return false ;

// If base is below or equal to 10, then all

// digits should be from 0 to 9.

else if (base <= 10)

{

for ( int i = 0; i < str.length(); i++)

if (!(str[i] >= '0' and

str[i] < ( '0' + base)))

return false ;

}

// If base is below or equal to 16, then all

// digits should be from 0 to 9 or from 'A'

else

{

for ( int i = 0; i < str.length(); i++)

if (! ((str[i] >= '0' &&

str[i] < ( '0' + base)) ||

(str[i] >= 'A' &&

str[i] < ( 'A' + base - 10))

))

return false ;

}

return true ;

}

// Driver code

int main()

{

string str = "AF87" ;

if (isInGivenBase(str, 16))

cout << "Yes" ;

else

cout << "No" ;

return 0;

}

// Java program to check if given

// number is in given base or not.

class Geeks {

static boolean isInGivenBase(String str, int base)

{

// Allowed bases are till 16 (Hexadecimal)

if (base > 16 )

return false ;

// If base is below or equal to 10, then all

// digits should be from 0 to 9.

else if (base <= 10 )

{

for ( int i = 0 ; i < str.length(); i++)

if (!(str.charAt(i) >= '0' &&

str.charAt(i) < ( '0' + base)))

return false ;

}

// If base is below or equal to 16, then all

// digits should be from 0 to 9 or from 'A'

else

{

for ( int i = 0 ; i < str.length(); i++)

if (! ((str.charAt(i) >= '0' &&

str.charAt(i) < ( '0' + base)) ||

(str.charAt(i) >= 'A' &&

str.charAt(i) < ( 'A' + base - 10 ))

))

return false ;

}

return true ;

}

// Driver Class

public static void main(String args[])

{

String str = "AF87" ;

if (isInGivenBase(str, 16 ) == true )

System.out.println( "Yes" );

else

System.out.println( "No" );

}

}

// This code is contributed by ankita_saini

# Python3 program to check if given

# number is in given base or not.

def isInGivenBase( Str , base):

# Allowed bases are till 16 (Hexadecimal)

if (base > 16 ):

return False

# If base is below or equal to 10,

# then all digits should be from 0 to 9.

elif (base < = 10 ):

for i in range ( len ( Str )):

if ( Str [i].isnumeric() and

( ord ( Str [i]) > = ord ( '0' ) and

ord ( Str [i]) < ( ord ( '0' ) + base)) = = False ):

return False

# If base is below or equal to 16, then all

# digits should be from 0 to 9 or from 'A'

else :

for i in range ( len ( Str )):

if ( Str [i].isnumeric() and

(( ord ( Str [i]) > = ord ( '0' ) and

ord ( Str [i]) < ( ord ( '0' ) + base)) or

( ord ( Str [i]) > = ord ( 'A' ) and

ord ( Str [i]) < ( ord ( 'A' ) + base - 10 ))) = = False ):

return False

return True

# Driver code

Str = "AF87"

if (isInGivenBase( Str , 16 )):

print ( "Yes" )

else :

print ( "No" )

# This code is contributed by Mohit Kumar

// C# program to check if given

// number is in given base or not.

using System;

class GFG

{

static bool isInGivenBase(String str,

int bas)

{

// Allowed base are

// till 16 (Hexadecimal)

if (bas > 16)

return false ;

// If bas is below or equal

// to 10, then all digits

// should be from 0 to 9.

else if (bas <= 10)

{

for ( int i = 0; i < str.Length; i++)

if (!(str[i] >= '0' &&

str[i] < ( '0' + bas)))

return false ;

}

// If base is below or equal

// to 16, then all digits should

// be from 0 to 9 or from 'A'

else

{

for ( int i = 0; i < str.Length; i++)

if (! ((str[i] >= '0' &&

str[i] < ( '0' + bas)) ||

(str[i] >= 'A' &&

str[i] < ( 'A' + bas - 10))

))

return false ;

}

return true ;

}

// Driver Code

public static void Main(String []args)

{

String str = "AF87" ;

if (isInGivenBase(str, 16) == true )

Console.WriteLine( "Yes" );

else

Console.WriteLine( "No" );

}

}

// This code is contributed

// by ankita_saini

<?php

// PHP program to check if given

// number is in given base or not.

function isInGivenBase( $str , $base )

{

// Allowed bases are till

// 16 (Hexadecimal)

if ( $base > 16)

return false;

// If base is below or equal to

// 10, then all digits should

// be from 0 to 9.

else if ( $base <= 10)

{

for ( $i = 0; $i < strlen ( $str ); $i ++)

if (!( $str [ $i ] >= '0' and

$str [ $i ] < ( '0' + $base )))

return false;

}

// If base is below or equal to 16,

// then all digits should be from

// 0 to 9 or from 'A'

else

{

for ( $i = 0; $i < strlen ( $str ); $i ++)

if (! (( $str [ $i ] >= '0' &&

$str [ $i ] < ( '0' + $base )) ||

( $str [ $i ] >= 'A' &&

$str [ $i ] < ( 'A' + $base - 10))

))

return false;

}

return true;

}

// Driver code

$str = "AF87" ;

if (isInGivenBase( $str , 16))

echo "Yes" ;

else

echo "No" ;

// This code is contributed by jit_t

?>

<script>

// Javascript program to check if given

// number is in given base or not.

function isInGivenBase(str, bas)

{

// Allowed base are

// till 16 (Hexadecimal)

if (bas > 16)

return false ;

// If bas is below or equal

// to 10, then all digits

// should be from 0 to 9.

else if (bas <= 10)

{

for (let i = 0; i < str.length; i++)

if (!(str[i].charCodeAt() >=

'0' .charCodeAt() &&

str[i].charCodeAt() <

( '0' .charCodeAt() + bas)))

return false ;

}

// If base is below or equal

// to 16, then all digits should

// be from 0 to 9 or from 'A'

else

{

for (let i = 0; i < str.length; i++)

if (! ((str[i].charCodeAt() >=

'0' .charCodeAt() &&

str[i].charCodeAt() <

( '0' .charCodeAt() + bas)) ||

(str[i].charCodeAt() >=

'A' .charCodeAt() &&

str[i].charCodeAt() <

( 'A' .charCodeAt() + bas - 10))

))

return false ;

}

return true ;

}

let str = "AF87" ;

if (isInGivenBase(str, 16) == true )

document.write( "Yes" );

else

document.write( "No" );

</script>