这个 无序的多重映射::计数() 在C++ STL中是一个内置函数,它返回容器中的元素数量,这些容器的键等于在参数中传递的密钥。
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语法:
unordered_multimap_name.count(key)
参数: 该函数只接受一个强制参数 钥匙 它指定要返回其在无序的_multimap容器中的计数的键。
返回值: 它返回一个无符号整数类型,表示 钥匙 在容器中发生。
以下程序说明了上述功能:
项目1:
// C++ program to illustrate the // unordered_multimap::count() #include <bits/stdc++.h> using namespace std; int main() { // declaration unordered_multimap< int , int > sample; // inserts key and element sample.insert({ 10, 100 }); sample.insert({ 10, 100 }); sample.insert({ 20, 200 }); sample.insert({ 30, 300 }); sample.insert({ 30, 150 }); cout << "10 occurs " << sample.count(10) << " times" ; cout << "20 occurs " << sample.count(20) << " times" ; cout << "13 occurs " << sample.count(13) << " times" ; cout << "30 occurs " << sample.count(30) << " times" ; return 0; } |
输出:
10 occurs 2 times 20 occurs 1 times 13 occurs 0 times 30 occurs 2 times
项目2:
// C++ program to illustrate the // unordered_multimap::count() #include <bits/stdc++.h> using namespace std; int main() { // declaration unordered_multimap< char , char > sample; // inserts key and element sample.insert({ 'a' , 'b' }); sample.insert({ 'a' , 'b' }); sample.insert({ 'b' , 'c' }); sample.insert({ 'r' , 'a' }); sample.insert({ 'r' , 'b' }); cout << "a occurs " << sample.count( 'a' ) << " times" ; cout << "b occurs " << sample.count( 'b' ) << " times" ; cout << "z occurs " << sample.count( 'z' ) << " times" ; cout << "r occurs " << sample.count( 'r' ) << " times" ; return 0; } |
输出:
a occurs 2 times b occurs 1 times z occurs 0 times r occurs 2 times
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