C++ STL中的无序序MultIMAP CONTUTE()函数

这个 无序的多重映射::计数() 在C++ STL中是一个内置函数,它返回容器中的元素数量,这些容器的键等于在参数中传递的密钥。

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语法:

unordered_multimap_name.count(key)

参数: 该函数只接受一个强制参数 钥匙 它指定要返回其在无序的_multimap容器中的计数的键。

返回值: 它返回一个无符号整数类型,表示 钥匙 在容器中发生。

以下程序说明了上述功能:

项目1:

// C++ program to illustrate the
// unordered_multimap::count()
#include <bits/stdc++.h>
using namespace std;
int main()
{
// declaration
unordered_multimap< int , int > sample;
// inserts key and element
sample.insert({ 10, 100 });
sample.insert({ 10, 100 });
sample.insert({ 20, 200 });
sample.insert({ 30, 300 });
sample.insert({ 30, 150 });
cout << "10 occurs " << sample.count(10)
<< " times" ;
cout << "20 occurs " << sample.count(20)
<< " times" ;
cout << "13 occurs " << sample.count(13)
<< " times" ;
cout << "30 occurs " << sample.count(30)
<< " times" ;
return 0;
}


输出:

10 occurs 2 times
20 occurs 1 times
13 occurs 0 times
30 occurs 2 times

项目2:

// C++ program to illustrate the
// unordered_multimap::count()
#include <bits/stdc++.h>
using namespace std;
int main()
{
// declaration
unordered_multimap< char , char > sample;
// inserts key and element
sample.insert({ 'a' , 'b' });
sample.insert({ 'a' , 'b' });
sample.insert({ 'b' , 'c' });
sample.insert({ 'r' , 'a' });
sample.insert({ 'r' , 'b' });
cout << "a occurs " << sample.count( 'a' )
<< " times" ;
cout << "b occurs " << sample.count( 'b' )
<< " times" ;
cout << "z occurs " << sample.count( 'z' )
<< " times" ;
cout << "r occurs " << sample.count( 'r' )
<< " times" ;
return 0;
}


输出:

a occurs 2 times
b occurs 1 times
z occurs 0 times
r occurs 2 times

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