数学Atan2() 是一个内置的数学类方法,它返回的角度的切线是两个指定数字的商。基本上,它返回一个角度θ(以弧度为单位),其值介于-π和π之间。这是正x轴和点(x,y)之间的逆时针角度。
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语法:
public static double Atan2(double value1, double value2)
参数:
价值1: 类型点的y坐标 系统双重的 . 价值2: 类型点的x坐标 系统双重的 .
返回类型: 返回类型的角度Θ 系统双重的 .
注: 角θ(以弧度为单位),使得≤ θ ≤ π、 tan(θ)=value1/value2,其中(value1,value2)是笛卡尔平面上的点。返回值有两个条件:
- 当点位于笛卡尔平面上时
- 当点位于象限的边界上时
下面是演示数学的程序。当点 位于笛卡尔平面 :
- 项目1: 如果点(值1,值2)位于第一象限,即0
// C# program to demonstrate the
// Math.Atan2() Method when point
// lies in first quadrant
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(10, 10) * (180 / Math.PI));
}
}
输出:45
- 项目2: 如果点(值1,值2)位于第二象限,即π/2
// C# program to demonstrate the
// Math.Atan2() Method when point
// lies in second quadrant
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(10, -10) * (180 / Math.PI));
}
}
输出:135
- 方案3: 如果点(值1,值2)位于第三象限,即-π
// C# program to demonstrate the
// Math.Atan2() Method when point
// lies in third quadrant
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(-10, -10) * (180 / Math.PI));
}
}
输出:-135
- 方案4: 如果点(值1,值2)位于第四象限,即-π/2
// C# program to demonstrate the
// Math.Atan2() Method when point
// lies in fourth quadrant
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(-10, 10) * (180 / Math.PI));
}
}
输出:-45
下面是演示数学的程序。当点 位于象限的边界上 :
- 项目1: 如果value1为0,value2不为负,即θ=0
// C# program to demonstrate the
// Math.Atan2() Method when value1
// is 0 and value2 is not negative
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(0, 10) * (180 / Math.PI));
}
}
输出:0
- 项目2: 如果value1为0,value2为负,即θ=π
// C# program to demonstrate the
// Math.Atan2() Method when value1
// is 0 and value2 is negative
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(0, -10) * (180 / Math.PI));
}
}
输出:180
- 方案3: 如果值1为正,值2为0,即θ=π/2
// C# program to demonstrate the
// Math.Atan2() Method value1 is
// positive and value2 is 0
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(10, 0) * (180 / Math.PI));
}
}
输出:90
- 方案4: 如果value1为负,value2为0,即θ=-π/2
// C# program to demonstrate the
// Math.Atan2() Method value1 is
// negative and value2 is 0
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(-10, 0) * (180 / Math.PI));
}
}
输出:-90
- 方案5: 如果value1为0,value2为0,即θ=0
// C# program to demonstrate the
// Math.Atan2() Method value1 is
// 0 and value2 is 0
using
System;
class
Geeks {
// Main method
public
static
void
Main()
{
// using Math.Atan2() Method &
// converting result into degree
Console.Write(Math.Atan2(0, 0) * (180 / Math.PI));
}
}
输出:0
要记住的要点: 如果value1或value2为 楠 ,或者如果value1和value1 积极信心 或 负信心 ,该方法返回 楠 .
例子:
// C# program to demonstrate the Math.Atan2() // method when arguments are of type either // NaN, PositiveInfinity or NegativeInfinity using System; class Geeks { // Main method public static void Main() { double val1 = 0; double val2 = Double.NaN; Console.WriteLine(Math.Atan2(val1, val2)); double val3 = Double.NaN; double val4 = Double.NaN; Console.WriteLine(Math.Atan2(val3, val4)); double val5 = Double.NaN; double val6 = Double.PositiveInfinity; Console.WriteLine(Math.Atan2(val5, val6)); double val7 = Double.PositiveInfinity; double val8 = Double.NegativeInfinity; Console.WriteLine(Math.Atan2(val7, val8)); } } |
输出:
NaN NaN NaN NaN
参考: https://msdn.microsoft.com/en-us/library/system.math.atan2
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