给定行数和列数，使用循环打印相应的纳粹党徽图案。 注： 行数和列数应相同，且为奇数。这将产生一个完美的万字图案。 例如：
null
Input : row = 7, column = 7 Output:* * * * ** ** ** * * * * * * * * * ** * * * *Input : row = 11, column = 11Output :* * * * * * ** ** ** ** ** * * * * * * * * * * * * * * * * * * * * * * * * *
建议：请先在{IDE}上尝试您的方法，然后再继续解决方案 下面是打印纳粹党徽图案的实现。
C++
// C++ implementation to // print swastika pattern #include <bits/stdc++.h> using namespace std; // function to print swastika void swastika( int row, int col) { for ( int i = 0; i < row; i++) { for ( int j = 0; j < col; j++) { // checking if i < row/2 if (i < row / 2) { // checking if j<col/2 if (j < col / 2) { // print '*' if j=0 if (j == 0) cout << "*" ; // else print space else cout << " " << " " ; } // check if j=col/2 else if (j == col / 2) cout << " *" ; else { // if i=0 then first row will have '*' if (i == 0) cout << " *" ; } } else if (i == row / 2) cout << "* " ; else { // middle column and last column will have '*' // after i > row/2 if (j == col / 2 || j == col - 1) cout << "* " ; // last row else if (i == row - 1) { // last row will be have '*' if // j <= col/2 or if it is last column if (j <= col / 2 || j == col - 1) cout << "* " ; else cout << " " << " " ; } else cout << " " << " " ; } } cout << "" ; } } // driver code int main() { // odd number of row and column // to get perfect swastika int row = 7, col = 7; // function calling swastika(row, col); return 0; } |
JAVA
// Java implementation to // print swastika pattern class GFG { // function to print swastika static void swastika( int row, int col) { for ( int i = 0 ; i < row; i++) { for ( int j = 0 ; j < col; j++) { // checking if i < row/2 if (i < row / 2 ) { // checking if j<col/2 if (j < col / 2 ) { // print '*' if j=0 if (j == 0 ) System.out.print( "*" ); // else print space else System.out.print( " " + " " ); } // check if j=col/2 else if (j == col / 2 ) System.out.print( " *" ); else { // if i=0 then first row // will have '*' if (i == 0 ) System.out.print( " *" ); } } else if (i == row / 2 ) System.out.print( "* " ); else { // middle column and last column // will have '*' after i > row/2 if (j == col / 2 || j == col - 1 ) System.out.print( "* " ); // last row else if (i == row - 1 ) { // last row will be have '*' if // j <= col/2 or if it is last column if (j <= col / 2 || j == col - 1 ) System.out.print( "* " ); else System.out.print( " " + " " ); } else System.out.print( " " + " " ); } } System.out.print( "" ); } } // Driver code public static void main (String[] args) { // odd number of row and column // to get perfect swastika int row = 7 , col = 7 ; // function calling swastika(row, col); } } // This code is contributed by Anant Agarwal. |
Python3
# Python3 implementation to print swastika pattern # Function to print swastika def swastika(row,col): for i in range (row): for j in range (col): # checking if i < row/2 if (i < row / / 2 ): # checking if j<col/2 if (j < col / / 2 ): # print '*' if j=0 if (j = = 0 ): print ( "*" , end = "") # else print space else : print ( " " , end = " " ) # check if j=col/2 elif (j = = col / / 2 ): print ( " *" , end = "") else : # if i=0 then first row will have '*' if (i = = 0 ): print ( " *" , end = "") elif (i = = row / / 2 ): print ( "* " , end = "") else : # middle column and last column will # have '*' after i > row/2 if (j = = col / / 2 or j = = col - 1 ): print ( "* " , end = "") # last row elif (i = = row - 1 ): # last row will be have '*' if # j <= col/2 or if it is last column if (j < = col / / 2 or j = = col - 1 ): print ( "* " , end = "") else : print ( " " , end = " " ) else : print ( " " , end = " " ) print () # Driver code # odd number of row and column # to get perfect swastika row = 7 ; col = 7 # Function calling swastika(row, col) # This code is contributed by Azkia Anam. |
C#
// C# implementation to print swastika pattern using System; class GFG { // function to print swastika static void swastika( int row, int col) { for ( int i = 0; i < row; i++) { for ( int j = 0; j < col; j++) { // checking if i < row/2 if (i < row / 2) { // checking if j < col/2 if (j < col / 2) { // print '*' if j = 0 if (j == 0) Console.Write( "*" ); // else print space else Console.Write( " " + " " ); } // check if j = col/2 else if (j == col / 2) Console.Write( " *" ); else { // if i=0 then first row // will have '*' if (i == 0) Console.Write( " *" ); } } else if (i == row / 2) Console.Write( "* " ); else { // middle column and last column // will have '*' after i > row/2 if (j == col / 2 || j == col - 1) Console.Write( "* " ); // last row else if (i == row - 1) { // last row will be have '*' if // j <= col/2 or if it is last column if (j <= col / 2 || j == col - 1) Console.Write( "* " ); else Console.Write( " " + " " ); } else Console.Write( " " + " " ); } } Console.WriteLine(); } } // Driver code public static void Main () { // odd number of row and column // to get perfect swastika int row = 7, col = 7; // function calling swastika(row, col); } } // This code is contributed by vt_m. |
PHP
<?php // PHP implementation to // print swastika pattern // function to print swastika function swastika( $row , $col ) { for ( $i = 0; $i < $row ; $i ++) { for ( $j = 0; $j < $col ; $j ++) { // checking if i < row/2 if ( $i < floor ( $row / 2)) { // checking if j<col/2 if ( $j < floor ( $col / 2)) { // print '*' if j=0 if ( $j == 0) echo "*" ; // else print space else echo " " . " " ; } // check if j=col/2 else if ( $j == floor ( $col / 2)) echo " *" ; else { // if i=0 then first // row will have '*' if ( $i == 0) echo " *" ; } } else if ( $i == floor ( $row / 2)) echo "* " ; else { // middle column and last // column will have '*' // after i > row/2 if ( $j == floor ( $col / 2 )|| $j == $col - 1) echo "* " ; // last row else if ( $i == $row - 1) { // last row will be have // '*' if j <= col/2 or // if it is last column if ( $j <= floor ( $col / 2) || $j == $col - 1) echo "* " ; else echo " " . " " ; } else echo " " . " " ; } } echo "" ; } } // Driver Code // odd number of row // and column to get // perfect swastika $row = 7; $col = 7; // function calling swastika( $row , $col ); // This code is contributed by ajit ?> |
Javascript
<script> // JavaScript implementation to // print swastika pattern // function to print swastika function swastika(row, col) { for ( var i = 0; i < row; i++) { for ( var j = 0; j < col; j++) { // checking if i < row/2 if (i < Math.floor(row / 2)) { // checking if j<col/2 if (j < Math.floor(col / 2)) { // print '*' if j=0 if (j == 0) document.write( "*" ); // else print space else document.write( " " + " " ); } // check if j=col/2 else if (j == Math.floor(col / 2)) document.write( " *" ); else { // if i=0 then first row will have '*' if (i == 0) document.write( " *" ); } } else if (i == Math.floor(row / 2)) document.write( "* " ); else { // middle column and last column will have '*' // after i > row/2 if (j == Math.floor(col / 2) || j == col - 1) document.write( "* " ); // last row else if (i == row - 1) { // last row will be have '*' if // j <= col/2 or if it is last column if (j <= Math.floor(col / 2) || j == col - 1) document.write( "* " ); else document.write( " " + " " ); } else document.write( " " + " " ); } } document.write( "<br>" ); } } // driver code // odd number of row and column // to get perfect swastika var row = 7, col = 7; // function calling swastika(row, col); // This code is contributed by rdtank. </script> |
输出：
* * * * ** ** ** * * * * * * * * * ** * * * *
© 版权声明
文章版权归作者所有，未经允许请勿转载。
THE END
![关于”PostgreSQL错误：关系[表]不存在“问题的原因和解决方案-yiteyi-C++库](https://www.yiteyi.com/wp-content/themes/zibll/img/thumbnail.svg)
