Python字符串casefold（）方法-yiteyi-C++库

Python字符串 casefold（） 方法用于实现无大小写字符串匹配。类似于下（）字符串方法，但大小写 删除所有大小写差异 以一串的形式出现。i、 e在比较时忽略案例。

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语法：

一串casefold（）

参数：

casefold（）方法不接受任何参数。

返回值：

它返回大小写折叠字符串，并将字符串转换为小写。

示例1：转换小写字符串

Python3

                         # Python program to convert string in lower case                       
                         string                                     =                                     "GEEKSFORGEEKS"                       
                                   
                         # print lowercase string                       
                         print                                     (                                     "lowercase string: "                                     ,string.casefold())                       

输出：

lowercase string: geeksforgeeks

示例2：检查字符串是否为回文

Python3

                         # Program to check if a string                       
                         #  is palindrome or not                       
                                   
                         # change this value for a different output                       
                         str                                     =                                     'geeksforgeeks'                       
                                   
                         # make it suitable for caseless comparison                       
                         str                                     =                                     str                                     .casefold()                       
                                   
                         # reverse the string                       
                         rev_str                                     =                                     reversed                                     (                                     str                                     )                       
                                   
                         # check if the string is equal to its reverse                       
                         if                                     str                                     =                                     =                                     rev_str:                       
                                                 print                                     (                                     "palindrome"                                     )                       
                         else                                     :                       
                                                 print                                     (                                     "not palindrome"                                     )                       

输出：

not palindrome

例3：计算字符串中的元音

Python3

                         # Program to count                       
                         # the number of each                       
                         # vowel in a string                       
                                   
                         # string of vowels                       
                         v                                     =                                     'aeiou'                       
                                   
                         # change this value for a different result                       
                         str                                     =                                     'Hello, have you try geeksforgeeks?'                       
                                   
                         # input from the user                       
                         # str = input("Enter a string: ")                       
                                   
                         # caseless comparisions                       
                         str                                     =                                     str                                     .casefold()                       
                                   
                         # make a dictionary with                       
                         # each vowel a key and value 0                       
                         c                                     =                                     {}.fromkeys(v,                                     0                                     )                       
                                   
                         # count the vowels                       
                         for                                     char                                     in                                     str                                     :                       
                                                 if                                     char                                     in                                     c:                       
                                                 c[char]                                     +                                     =                                     1                       
                         print                                     (c)                       

输出：

{'a': 1, 'e': 6, 'i': 0, 'o': 3, 'u': 1}

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