画一个没有浮点运算的圆

// C++ code to demonstrate to draw

// circle without floating

// point arithmetic

#include <stdio.h>

void drawCircle( int r)

{

// Consider a rectangle of size N*N

int N = 2*r+1;

int x, y; // Coordinates inside the rectangle

// Draw a square of size N*N.

for ( int i = 0; i < N; i++)

{

for ( int j = 0; j < N; j++)

{

// Start from the left most corner point

x = i-r;

y = j-r;

// If this point is inside the circle, print it

if (x*x + y*y <= r*r+1 )

printf ( "." );

else // If outside the circle, print space

printf ( " " );

printf ( " " );

}

printf ( "" );

}

}

// Driver Program to test above function

int main()

{

drawCircle(8);

return 0;

}

// Java code to demonstrate to draw

// circle without floating

// point arithmetic

class GFG

{

static void drawCircle( int r)

{

// Consider a rectangle of size N*N

int N = 2 *r+ 1 ;

int x, y; // Coordinates inside the rectangle

// Draw a square of size N*N.

for ( int i = 0 ; i < N; i++)

{

for ( int j = 0 ; j < N; j++)

{

// Start from the left most corner point

x = i-r;

y = j-r;

// If this point is inside the circle, print it

if (x*x + y*y <= r*r+ 1 )

System.out.print( "." );

else

// If outside the circle, print space

System.out.print( " " );

System.out.print( " " );

}

System.out.println();

}

}

// Driver Program to test above function

public static void main(String arg[])

{

drawCircle( 8 );

}

}

// This code is contributed

// by Anant Agarwal.

# Python3 code to demonstrate to draw

# circle without floating

# point arithmetic

def drawCircle(r):

# Consider a rectangle of size N*N

N = 2 * r + 1

# Draw a square of size N*N.

for i in range (N):

for j in range (N):

# Start from the left most corner point

x = i - r

y = j - r

# If this point is inside the circle,

# print it

if x * x + y * y < = r * r + 1 :

print ( "." , end = " " )

# If outside the circle, print space

else :

print ( " " , end = " " )

print ()

# Driver Code

if __name__ = = "__main__" :

drawCircle( 8 )

# This code is contributed

# by vibhu4agarwal

// C# code to demonstrate to draw

// circle without floating

// point arithmetic

using System;

public class GFG{

static void drawCircle( int r)

{

// Consider a rectangle of size N*N

int N = 2*r+1;

int x, y; // Coordinates inside the rectangle

// Draw a square of size N*N.

for ( int i = 0; i < N; i++)

{

for ( int j = 0; j < N; j++)

{

// Start from the left most corner point

x = i-r;

y = j-r;

// If this point is inside the circle, print it

if (x*x + y*y <= r*r+1 )

Console.Write( "." );

else

// If outside the circle, print space

Console.Write( " " );

Console.Write( " " );

}

Console.WriteLine();

}

}

// Driver Program to test above function

static public void Main (){

drawCircle(8);

}

// This code is contributed

// by ajit.

}

<?php

// PHP code to demonstrate to draw circle

// without floating point arithmetic

function drawCircle( $r )

{

// Consider a rectangle of size N*N

$N = 2 * $r + 1;

$y ; // Coordinates inside the rectangle

// Draw a square of size N*N.

for ( $i = 0; $i < $N ; $i ++)

{

for ( $j = 0; $j < $N ; $j ++)

{

// Start from the left most

// corner point

$x = $i - $r ;

$y = $j - $r ;

// If this point is inside the

// circle, print it

if ( $x * $x + $y * $y <= $r * $r + 1)

echo ( "." );

else // If outside the circle,

// print space

echo ( " " );

echo ( " " );

}

echo "" ;

}

}

// Driver Code

drawCircle(8);

// This code is contributed by akt_mit

?>

<script>

function drawCircle(r)

{

// Consider a rectangle of size N*N

let N = 2*r+1;

let x, y; // Coordinates inside the rectangle

// Draw a square of size N*N.

for (let i = 0; i < N; i++)

{

for (let j = 0; j < N; j++)

{

// Start from the left most corner point

x = i - r;

y = j - r;

// If this point is inside the circle, print it

if (x * x + y * y <= r * r + 1 )

document.write( "." );

else

// If outside the circle, print space

document.write( " &nbsp" );

document.write( "&nbsp " );

}

document.write( "<br>" );

}

}

drawCircle(8);

// This code is contributed by avanitrachhadiya2155

</script>