检查强数的程序

强大的数字 数字的阶乘和等于原始数的数。给定一个数字,检查它是否为强数。 例如:

null
Input  : n = 145Output : YesSum of digit factorials = 1! + 4! + 5!                        = 1 + 24 + 120                        = 145Input :  n = 534Output : No

1) Initialize sum of factorials as 0. 2) For every digit d, do following   a) Add d! to sum of factorials.3) If sum factorials is same as given    number, return true.4) Else return false.

优化是预先计算从0到10的所有数字的阶乘。

C++

// C++ program to check if a number is
// strong or not.
#include <bits/stdc++.h>
using namespace std;
int f[10];
// Fills factorials of digits from 0 to 9.
void preCompute()
{
f[0] = f[1] = 1;
for ( int i = 2; i<10; ++i)
f[i] = f[i-1] * i;
}
// Returns true if x is Strong
bool isStrong( int x)
{
int factSum = 0;
// Traverse through all digits of x.
int temp = x;
while (temp)
{
factSum += f[temp%10];
temp /= 10;
}
return (factSum == x);
}
// Driver code
int main()
{
preCompute();
int x = 145;
isStrong(x) ? cout << "Yes" : cout << "No" ;
x = 534;
isStrong(x) ? cout << "Yes" : cout << "No" ;
return 0;
}


JAVA

// Java program to check if
// a number is Strong or not
class CheckStrong
{
static int f[] = new int [ 10 ];
// Fills factorials of digits from 0 to 9.
static void preCompute()
{
f[ 0 ] = f[ 1 ] = 1 ;
for ( int i = 2 ; i< 10 ; ++i)
f[i] = f[i- 1 ] * i;
}
// Returns true if x is Strong
static boolean isStrong( int x)
{
int factSum = 0 ;
// Traverse through all digits of x.
int temp = x;
while (temp> 0 )
{
factSum += f[temp% 10 ];
temp /= 10 ;
}
return (factSum == x);
}
// main function
public static void main (String[] args)
{
// calling preCompute
preCompute();
// first pass
int x = 145 ;
if (isStrong(x))
{
System.out.println( "Yes" );
}
else
System.out.println( "No" );
// second pass
x = 534 ;
if (isStrong(x))
{
System.out.println( "Yes" );
}
else
System.out.println( "No" );
}
}


Python3

# Python program to check if a number is
# strong or not.
f = [ None ] * 10
# Fills factorials of digits from 0 to 9.
def preCompute() :
f[ 0 ] = f[ 1 ] = 1 ;
for i in range ( 2 , 10 ) :
f[i] = f[i - 1 ] * i
# Returns true if x is Strong
def isStrong(x) :
factSum = 0
# Traverse through all digits of x.
temp = x
while (temp) :
factSum = factSum + f[temp % 10 ]
temp = temp / / 10
return (factSum = = x)
# Driver code
preCompute()
x = 145
if (isStrong(x) ) :
print ( "Yes" )
else :
print ( "No" )
x = 534
if (isStrong(x)) :
print ( "Yes" )
else :
print ( "No" )
# This code is contributed by Nikita Tiwari.


C#

// C# program to check if
// a number is Strong or not
using System;
class CheckStrong
{
static int []f = new int [10];
// Fills factorials of digits from 0 to 9.
static void preCompute()
{
f[0] = f[1] = 1;
for ( int i = 2; i < 10; ++i)
f[i] = f[i - 1] * i;
}
// Returns true if x is Strong
static bool isStrong( int x)
{
int factSum = 0;
// Traverse through all digits of x.
int temp = x;
while (temp > 0)
{
factSum += f[temp % 10];
temp /= 10;
}
return (factSum == x);
}
// Driver Code
public static void Main ()
{
// calling preCompute
preCompute();
// first pass
int x = 145;
if (isStrong(x))
{
Console.WriteLine( "Yes" );
}
else
Console.WriteLine( "No" );
// second pass
x = 534;
if (isStrong(x))
{
Console.WriteLine( "Yes" );
}
else
Console.WriteLine( "No" );
}
}
// This code is contributed by Nitin Mittal.


PHP

<?php
// PHP program to check if a number
// is strong or not.
$f [10] = array ();
// Fills factorials of digits
// from 0 to 9.
function preCompute()
{
global $f ;
$f [0] = $f [1] = 1;
for ( $i = 2; $i < 10; ++ $i )
$f [ $i ] = $f [ $i - 1] * $i ;
}
// Returns true if x is Strong
function isStrong( $x )
{
global $f ;
$factSum = 0;
// Traverse through all digits of x.
$temp = $x ;
while ( $temp )
{
$factSum += $f [ $temp % 10];
$temp = (int) $temp / 10;
}
return ( $factSum == $x );
}
// Driver code
preCompute();
$x = 145;
if (isStrong(! $x ))
echo "Yes" ;
else
echo "No" ;
$x = 534;
if (isStrong( $x ))
echo "Yes" ;
else
echo "No" ;
// This code is contributed by jit_t
?>


Javascript

<script>
// Javascript program to check if a number is
// strong or not.
let f = new Array(10);
// Fills factorials of digits from 0 to 9.
function preCompute()
{
f[0] = f[1] = 1;
for (let i = 2; i<10; ++i)
f[i] = f[i-1] * i;
}
// Returns true if x is Strong
function isStrong(x)
{
let factSum = 0;
// Traverse through all digits of x.
let temp = x;
while (temp)
{
factSum += f[temp%10];
temp = Math.floor(temp/10);
}
return (factSum == x);
}
// Driver code
preCompute();
let x = 145;
isStrong(x) ? document.write( "Yes" + "<br>" ) :
document.write( "No" + "<br>" );
x = 534;
isStrong(x) ? document.write( "Yes" + "<br>" ) :
document.write( "No" + "<br>" );
//This code is contributed by Mayank Tyagi
</script>


输出:

YesNo

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