给定一个数组,它可以有4种类型。 (a) 上升的 (b) 下降的 (c) 上升旋转 (d) 下降旋转 找出它是哪种数组,并返回该数组的最大值。
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例如:
Input : arr[] = { 2, 1, 5, 4, 3}Output : Descending rotated with maximum element 5Input : arr[] = { 3, 4, 5, 1, 2}Output : Ascending rotated with maximum element 5
被问到: 亚马逊采访
实施:
1- First, check if the whole array is in increasing order, if yes then print arr[n-1]. and return.2- If above statement doesn't run even single time that means an array is in decreasing order from starting. Two cases arise: a) Check if the whole array is in decreasing order, if yes then print arr[0] and return. (b) Otherwise, the array is descending rotated and the maximum element will be the index before which array was decreasing.3- If first point partially satisfies that means the whole array is not in increasing order that means an array is ascending rotated and the maximum element will be the point from where it starts decreasing.
C++
// C++ program to find type of array, ascending // descending, clockwise rotated or anti-clockwise // rotated. #include <bits/stdc++.h> using namespace std; // Function to find the type of an array // and maximum element in it. void findType( int arr[], int n) { int i = 0; // Check if the array is in ascending order while (i < n - 1 && arr[i] <= arr[i + 1]) i++; // If i reaches to last index that means // all elements are in increasing order if (i == n - 1) { cout << "Ascending with maximum element = " << arr[n - 1] << endl; return ; } // If first element is greater than next one if (i == 0) { while (i < n - 1 && arr[i] >= arr[i + 1]) i++; // If i reaches to last index if (i == n - 1) { cout << "Descending with maximum element = " << arr[0] << endl; return ; } // If the whole array is not in decreasing order // that means it is first decreasing then // increasing, i.e., descending rotated, so // its maximum element will be the point breaking // the order i.e. i so, max will be i+1 if (arr[0] < arr[i + 1]) { cout << "Descending rotated with maximum element = " << max(arr[0], arr[i + 1]) << endl; return ; } else { cout << "Ascending rotated with maximum element = " << max(arr[0], arr[i + 1]) << endl; return ; } } // If whole array is not increasing that means at some // point it is decreasing, which makes it ascending rotated // with max element as the decreasing point if (i < n - 1 && arr[0] > arr[i + 1]) { cout << "Ascending rotated with maximum element = " << max(arr[i], arr[0]) << endl; return ; } cout << "Descending rotated with maximum element " << max(arr[i], arr[0]) << endl; } // Driver code int main() { int arr1[] = { 4, 5, 6, 1, 2, 3 }; // Ascending rotated int n = sizeof (arr1) / sizeof (arr1[0]); findType(arr1, n); int arr2[] = { 2, 1, 7, 5, 4, 3 }; // Descending rotated n = sizeof (arr2) / sizeof (arr2[0]); findType(arr2, n); int arr3[] = { 1, 2, 3, 4, 5, 8 }; // Ascending n = sizeof (arr3) / sizeof (arr3[0]); findType(arr3, n); int arr4[] = { 9, 5, 4, 3, 2, 1 }; // Descending n = sizeof (arr4) / sizeof (arr4[0]); findType(arr4, n); return 0; } |
JAVA
// Java program to find type of array, ascending // descending, clockwise rotated or anti-clockwise // rotated. import java.io.*; class GFG { public static int max( int a, int b) { return (a > b) ? a : b; } // Function to find the type of an array // and maximum element in it public static void findType( int arr[]) { int i = 0 ; int n = arr.length; // Check if the array is in ascending order while (i < n - 1 && arr[i] <= arr[i + 1 ]) i++; // If i reaches to last index that means // all elements are in increasing order if (i == n - 1 ) { System.out.println( "Ascending with maximum element = " + arr[n - 1 ]); return ; } // If first element is greater than next one if (i == 0 ) { while (i < n - 1 && arr[i] >= arr[i + 1 ]) i++; // If i reaches to last index if (i == n - 1 ) { System.out.println( "Descending with maximum " + "element = " + arr[ 0 ]); return ; } // If the whole array is not in decreasing order // that means it is first decreasing then // increasing, i.e., descending rotated, so // its maximum element will be the point breaking // the order i.e. i so, max will be i+1 if (arr[ 0 ] < arr[i + 1 ]) { System.out.println( "Descending rotated with" + " maximum element = " + max(arr[ 0 ], arr[i + 1 ])); return ; } else { System.out.println( "Ascending rotated with" + " maximum element = " + max(arr[ 0 ], arr[i + 1 ])); return ; } } // If whole array is not increasing that means at some // point it is decreasing, which makes it ascending rotated // with max element as the decreasing point if (i < n - 1 && arr[ 0 ] > arr[i + 1 ]) { System.out.println( "Ascending rotated with maximum" + " element = " + max(arr[i], arr[ 0 ])); return ; } System.out.println( "Descending rotated with maximum " + "element " + max(arr[i], arr[ 0 ])); } public static void main(String[] args) { int arr1[] = { 4 , 5 , 6 , 1 , 2 , 3 }; // Ascending rotated findType(arr1); int arr2[] = { 2 , 1 , 7 , 5 , 4 , 3 }; // Descending rotated findType(arr2); int arr3[] = { 1 , 2 , 3 , 4 , 5 , 8 }; // Ascending findType(arr3); int arr4[] = { 9 , 5 , 4 , 3 , 2 , 1 }; // Descending findType(arr4); } } |
Python3
# Python3 program to find type of array, ascending # descending, clockwise rotated or anti-clockwise # rotated. def findType(arr, n) : i = 0 ; # Check if the array is in ascending order while (i < n - 1 and arr[i] < = arr[i + 1 ]) : i = i + 1 # If i reaches to last index that means # all elements are in increasing order if (i = = n - 1 ): print (( "Ascending with maximum element = " + str (arr[n - 1 ]))) return None # If first element is greater than next one if (i = = 0 ): while (i < n - 1 and arr[i] > = arr[i + 1 ]): i = i + 1 ; # If i reaches to last index if (i = = n - 1 ): print (( "Descending with maximum element = " + str (arr[ 0 ]))) return None # If the whole array is not in decreasing order # that means it is first decreasing then # increasing, i.e., descending rotated, so # its maximum element will be the point breaking # the order i.e. i so, max will be i + 1 if (arr[ 0 ] < arr[i + 1 ]): print (( "Descending rotated with maximum element = " + str ( max (arr[ 0 ], arr[i + 1 ])))) return None else : print (( "Ascending rotated with maximum element = " + str ( max (arr[ 0 ], arr[i + 1 ])))) return None # If whole array is not increasing that means at some # point it is decreasing, which makes it ascending rotated # with max element as the decreasing point if (i < n - 1 and arr[ 0 ] > arr[i + 1 ]): print (( "Ascending rotated with maximum element = " + str ( max (arr[i], arr[ 0 ])))) return None print (( "Descending rotated with maximum element " + str ( max (arr[i], arr[ 0 ])))) # Driver code if __name__ = = '__main__' : arr1 = [ 4 , 5 , 6 , 1 , 2 , 3 ] # Ascending rotated n = len (arr1) findType(arr1, n); arr2 = [ 2 , 1 , 7 , 5 , 4 , 3 ] # Descending rotated n = len (arr2) findType(arr2, n); arr3 = [ 1 , 2 , 3 , 4 , 5 , 8 ] # Ascending n = len (arr3) findType(arr3, n); arr4 = [ 9 , 5 , 4 , 3 , 2 , 1 ] # Descending n = len (arr4) findType(arr4, n); # this code is contributed by YatinGupta |
C#
// C# program to find type of array, ascending // descending, clockwise rotated or anti-clockwise // rotated. using System; class GFG { public static int max( int a, int b) { return (a > b) ? a : b; } // Function to find the type of an array // and maximum element in it public static void findType( int [] arr) { int i = 0; int n = arr.Length; // Check if the array is in ascending // order while (i < n - 1 && arr[i] <= arr[i + 1]) i++; // If i reaches to last index that means // all elements are in increasing order if (i == n - 1) { Console.WriteLine( "Ascending with " + "maximum element = " + arr[n - 1]); return ; } // If first element is greater than // next one if (i == 0) { while (i < n - 1 && arr[i] >= arr[i + 1]) i++; // If i reaches to last index if (i == n - 1) { Console.WriteLine( "Descending with" + " maximum element = " + arr[0]); return ; } // If the whole array is not in // decreasing order that means it is // first decreasing then increasing, // i.e., descending rotated, so its // maximum element will be the point // breaking the order i.e. i so, max // will be i+1 if (arr[0] < arr[i + 1]) { Console.WriteLine( "Descending rotated" + " with maximum element = " + max(arr[0], arr[i + 1])); return ; } else { Console.WriteLine( "Ascending rotated" + " with maximum element = " + max(arr[0], arr[i + 1])); return ; } } // If whole array is not increasing that // means at some point it is decreasing, // which makes it ascending rotated with // max element as the decreasing point if (i < n - 1 && arr[0] > arr[i + 1]) { Console.WriteLine( "Ascending rotated" + " with maximum element = " + max(arr[i], arr[0])); return ; } Console.WriteLine( "Descending rotated with" + " maximum element " + max(arr[i], arr[0])); } // Driver code public static void Main() { // Ascending rotated int [] arr1 = { 4, 5, 6, 1, 2, 3 }; findType(arr1); // Descending rotated int [] arr2 = { 2, 1, 7, 5, 4, 3 }; findType(arr2); // Ascending int [] arr3 = { 1, 2, 3, 4, 5, 8 }; findType(arr3); // Descending int [] arr4 = { 9, 5, 4, 3, 2, 1 }; findType(arr4); } } // This code is contributed by nitin mittal. |
PHP
<?php // PHP program to find type // of array, ascending descending, // clockwise rotated or anti-clockwise // rotated. // Function to find the type // of an array and maximum // element in it. function findType( $arr , $n ) { $i = 0; // Check if the array is // in ascending order while ( $i < $n - 1 and $arr [ $i ] <= $arr [ $i + 1]) $i ++; // If i reaches to last index // that means all elements are // in increasing order if ( $i == $n - 1) { echo "Ascending with maximum " . "element = " , $arr [ $n - 1], "" ; return ; } // If first element is // greater than next one if ( $i == 0) { while ( $i < $n - 1 and $arr [ $i ] >= $arr [ $i + 1]) $i ++; // If i reaches to last index if ( $i == $n - 1) { echo "Descending with maximum " . "element = " , $arr [0], "" ; return ; } // If the whole array is not in // decreasing order that means // it is first decreasing then // increasing, i.e., descending // rotated, so its maximum element // will be the point breaking the // order i.e. i so, max will be i+1 if ( $arr [0] < $arr [ $i + 1]) { echo "Descending rotated with " . "maximum element = " , max( $arr [0], $arr [ $i + 1]), "" ; return ; } else { echo "Ascending rotated with " . "maximum element = " , max( $arr [0], $arr [ $i + 1]), "" ; return ; } } // If whole array is not increasing // that means at some point it is // decreasing, which makes it // ascending rotated with max element // as the decreasing point if ( $i < $n - 1 and $arr [0] > $arr [ $i + 1]) { echo "Ascending rotated with maximum " . "element = " , max( $arr [ $i ], $arr [0]), "" ; return ; } echo "Descending rotated with maximum " . "element " , max( $arr [ $i ], $arr [0]), "" ; } // Driver code // Ascending rotated $arr1 = array ( 4, 5, 6, 1, 2, 3); $n = count ( $arr1 ); findType( $arr1 , $n ); // Descending rotated $arr2 = array ( 2, 1, 7, 5, 4, 3); $n = count ( $arr2 ); findType( $arr2 , $n ); // Ascending $arr3 = array ( 1, 2, 3, 4, 5, 8); $n = count ( $arr3 ); findType( $arr3 , $n ); // Descending $arr4 = array ( 9, 5, 4, 3, 2, 1); $n = count ( $arr4 ); findType( $arr4 , $n ); // This code is contributed by anuj_67. ?> |
Javascript
<script> // Javascript program to find type of array, ascending // descending, clockwise rotated or anti-clockwise // rotated. function max(a, b) { return (a > b) ? a : b; } // Function to find the type of an array // and maximum element in it function findType(arr) { let i = 0; let n = arr.length; // Check if the array is in ascending // order while (i < n - 1 && arr[i] <= arr[i + 1]) i++; // If i reaches to last index that means // all elements are in increasing order if (i == n - 1) { document.write( "Ascending with " + "maximum element = " + arr[n - 1] + "</br>" ); return ; } // If first element is greater than // next one if (i == 0) { while (i < n - 1 && arr[i] >= arr[i + 1]) i++; // If i reaches to last index if (i == n - 1) { document.write( "Descending with" + " maximum element = " + arr[0]); return ; } // If the whole array is not in // decreasing order that means it is // first decreasing then increasing, // i.e., descending rotated, so its // maximum element will be the point // breaking the order i.e. i so, max // will be i+1 if (arr[0] < arr[i + 1]) { document.write( "Descending rotated" + " with maximum element = " + max(arr[0], arr[i + 1]) + "</br>" ); return ; } else { document.write( "Ascending rotated" + " with maximum element = " + max(arr[0], arr[i + 1]) + "</br>" ); return ; } } // If whole array is not increasing that // means at some point it is decreasing, // which makes it ascending rotated with // max element as the decreasing point if (i < n - 1 && arr[0] > arr[i + 1]) { document.write( "Ascending rotated" + " with maximum element = " + max(arr[i], arr[0]) + "</br>" ); return ; } document.write( "Descending rotated with" + " maximum element " + max(arr[i], arr[0]) + "</br>" ); } // Ascending rotated let arr1 = [ 4, 5, 6, 1, 2, 3 ]; findType(arr1); // Descending rotated let arr2 = [ 2, 1, 7, 5, 4, 3 ]; findType(arr2); // Ascending let arr3 = [ 1, 2, 3, 4, 5, 8 ]; findType(arr3); // Descending let arr4 = [ 9, 5, 4, 3, 2, 1 ]; findType(arr4); // This code is contributed by rameshtravel07. </script> |
输出:
Ascending rotated with maximum element = 6Descending rotated with maximum element = 7Ascending with maximum element = 8Descending with maximum element = 9
时间复杂性: O(n) 辅助空间: O(1)
另一种方法: 遍历数组一次,并存储数组中最小和最大元素的第一次和最后一次出现的索引。现在有四种情况:
- 如果最小元素的第一次出现在数组的开头,而最大元素的最后一次出现在数组的结尾,那么数组是按升序排列的。例如,{1,1,1,2,3,4,5,6,6,6}。
- 如果最大元素的第一次出现在数组的开头,而最小元素的最后一次出现在数组的末尾,那么数组是按降序排列的。例如,{6,6,6,5,4,3,2,1,1,1}。
- 如果最大元素的第一次出现等于最小元素的最后一次出现+1,则数组按降序旋转。例如,{3,2,1,1,1,6,6,5,4}。
- 如果最小元素的第一次出现等于最大元素的最后一次出现+1,则数组按升序旋转。例如,{4,5,6,6,6,1,1,2,3}。
以下是上述方法的实施情况:
C++
// C++ implementation of the approach #include <bits/stdc++.h> using namespace std; // Function to find the type of an array // and maximum element in it void findType( int arr[], int n) { // To store the minimum and the maximum // element from the array int min_element = INT_MAX, max_element = INT_MIN; // To store the first and the last occurrences // of the minimum and the maximum // element from the array int min_index1, max_index1, max_index2, min_index2; for ( int i = 0; i < n; i++) { // If new minimum is found if (arr[i] < min_element) { // Update the minimum so far // and its occurrences min_element = arr[i]; min_index1 = i; min_index2 = i; } // If current element is equal the found // minimum so far then update the last // occurrence of the minimum element else if (arr[i] == min_element) min_index2 = i; // If new maximum is found if (arr[i] > max_element) { // Update the maximum so far // and its occurrences max_element = arr[i]; max_index1 = i; max_index2 = i; } // If current element is equal the found // maximum so far then update the last // occurrence of the maximum element else if (arr[i] == max_element) max_index2 = i; } // First occurrence of minimum element is at the // beginning of the array and the last occurrence // of the maximum element is at the end of the // array then the array is sorted in ascending // For example, {1, 1, 1, 2, 3, 4, 5, 6, 6, 6} if (min_index1 == 0 && max_index2 == n - 1) { cout << "Ascending with maximum element = " << max_element << endl; } // First occurrence of maximum element is at the // beginning of the array and the last occurrence // of the minimum element is at the end of the // array then the array is sorted in descending // For example, {6, 6, 6, 5, 4, 3, 2, 1, 1, 1} else if (min_index2 == n - 1 && max_index1 == 0) { cout << "Descending with maximum element = " << max_element << endl; } // First occurrence of maximum element is equal // to the last occurrence of the minimum element + 1 // then the array is descending and rotated // For example, {3, 2, 1, 1, 1, 6, 6, 6, 5, 4} else if (max_index1 == min_index2 + 1) { cout << "Descending rotated with maximum element = " << max_element << endl; } // First occurrence of minimum element is equal // to the last occurrence of the maximum element + 1 // then the array is ascending and rotated // For example, {4, 5, 6, 6, 6, 1, 1, 1, 2, 3} else { cout << "Ascending rotated with maximum element = " << max_element << endl; } } // Driver code int main() { int arr[] = { 4, 5, 6, 6, 6, 1, 1, 1, 2, 3 }; int n = sizeof (arr) / sizeof (arr[0]); findType(arr, n); return 0; } |
JAVA
// Java implementation of the approach import java.util.*; class GFG { // Function to find the type of an array // and maximum element in it static void findType( int arr[], int n) { // To store the minimum and the maximum // element from the array int min_element = Integer.MAX_VALUE, max_element = Integer.MIN_VALUE; // To store the first and the last occurrences // of the minimum and the maximum // element from the array int min_index1 = - 1 , max_index1 = - 1 , max_index2 = - 1 , min_index2 = - 1 ; for ( int i = 0 ; i < n; i++) { // If new minimum is found if (arr[i] < min_element) { // Update the minimum so far // and its occurrences min_element = arr[i]; min_index1 = i; min_index2 = i; } // If current element is equal the found // minimum so far then update the last // occurrence of the minimum element else if (arr[i] == min_element) min_index2 = i; // If new maximum is found if (arr[i] > max_element) { // Update the maximum so far // and its occurrences max_element = arr[i]; max_index1 = i; max_index2 = i; } // If current element is equal the found // maximum so far then update the last // occurrence of the maximum element else if (arr[i] == max_element) max_index2 = i; } // First occurrence of minimum element is at the // beginning of the array and the last occurrence // of the maximum element is at the end of the // array then the array is sorted in ascending // For example, {1, 1, 1, 2, 3, 4, 5, 6, 6, 6} if (min_index1 == 0 && max_index2 == n - 1 ) { System.out.println( "Ascending with maximum" + " element = " + max_element); } // First occurrence of maximum element is at the // beginning of the array and the last occurrence // of the minimum element is at the end of the // array then the array is sorted in descending // For example, {6, 6, 6, 5, 4, 3, 2, 1, 1, 1} else if (min_index2 == n - 1 && max_index1 == 0 ) { System.out.println( "Descending with maximum" + " element = " + max_element); } // First occurrence of maximum element is equal // to the last occurrence of the minimum element + 1 // then the array is descending and rotated // For example, {3, 2, 1, 1, 1, 6, 6, 6, 5, 4} else if (max_index1 == min_index2 + 1 ) { System.out.println( "Descending rotated with " + "maximum element = " + max_element); } // First occurrence of minimum element is equal // to the last occurrence of the maximum element + 1 // then the array is ascending and rotated // For example, {4, 5, 6, 6, 6, 1, 1, 1, 2, 3} else { System.out.println( "Ascending rotated with " + "maximum element = " + max_element); } } // Driver code public static void main(String[] args) { int arr[] = { 4 , 5 , 6 , 6 , 6 , 1 , 1 , 1 , 2 , 3 }; int n = arr.length; findType(arr, n); } } // This code is contributed by Princi Singh |
Python3
# Python3 implementation of the approach # Function to find the type of an array # and maximum element in it import sys def findType(arr, n): # To store the minimum and the maximum # element from the array min_element = sys.maxsize; max_element = - sys.maxsize; # To store the first and the last occurrences # of the minimum and the maximum # element from the array min_index1 = - 1 ; max_index1 = - 1 , max_index2 = - 1 ; min_index2 = - 1 ; for i in range (n): # If new minimum is found if (arr[i] < min_element): # Update the minimum so far # and its occurrences min_element = arr[i]; min_index1 = i; min_index2 = i; # If current element is equal the found # minimum so far then update the last # occurrence of the minimum element elif (arr[i] = = min_element): min_index2 = i; # If new maximum is found if (arr[i] > max_element): # Update the maximum so far # and its occurrences max_element = arr[i]; max_index1 = i; max_index2 = i; # If current element is equal the found # maximum so far then update the last # occurrence of the maximum element elif (arr[i] = = max_element): max_index2 = i; # First occurrence of minimum element is at the # beginning of the array and the last occurrence # of the maximum element is at the end of the # array then the array is sorted in ascending # For example, 1, 1, 1, 2, 3, 4, 5, 6, 6, 6 if (min_index1 = = 0 and max_index2 = = n - 1 ): print ( "Ascending with maximum" , "element = " , max_element); # First occurrence of maximum element is at the # beginning of the array and the last occurrence # of the minimum element is at the end of the # array then the array is sorted in descending # For example, 6, 6, 6, 5, 4, 3, 2, 1, 1, 1 elif (min_index2 = = n - 1 and max_index1 = = 0 ): print ( "Descending with maximum" , "element = " , max_element); # First occurrence of maximum element is equal # to the last occurrence of the minimum element + 1 # then the array is descending and rotated # For example, [3, 2, 1, 1, 1, 6, 6, 6, 5, 4] elif (max_index1 = = min_index2 , 1 ): print ( "Descending rotated with" , "maximum element = " , max_element); # First occurrence of minimum element is equal # to the last occurrence of the maximum element + 1 # then the array is ascending and rotated # For example, [4, 5, 6, 6, 6, 1, 1, 1, 2, 3] else : print ( "Ascending rotated with" , "maximum element = " , max_element); # Driver code arr = [ 4 , 5 , 6 , 6 , 6 , 1 , 1 , 1 , 2 , 3 ]; n = len (arr); findType(arr, n); # This code is contributed by 29AjayKumar |
C#
// C# implementation of the approach using System; class GFG { // Function to find the type of an array // and maximum element in it static void findType( int []arr, int n) { // To store the minimum and the maximum // element from the array int min_element = int .MaxValue, max_element = int .MinValue; // To store the first and the last occurrences // of the minimum and the maximum // element from the array int min_index1 = -1, max_index1 = -1, max_index2 = -1, min_index2 = -1; for ( int i = 0; i < n; i++) { // If new minimum is found if (arr[i] < min_element) { // Update the minimum so far // and its occurrences min_element = arr[i]; min_index1 = i; min_index2 = i; } // If current element is equal the found // minimum so far then update the last // occurrence of the minimum element else if (arr[i] == min_element) min_index2 = i; // If new maximum is found if (arr[i] > max_element) { // Update the maximum so far // and its occurrences max_element = arr[i]; max_index1 = i; max_index2 = i; } // If current element is equal the found // maximum so far then update the last // occurrence of the maximum element else if (arr[i] == max_element) max_index2 = i; } // First occurrence of minimum element is at the // beginning of the array and the last occurrence // of the maximum element is at the end of the // array then the array is sorted in ascending // For example, {1, 1, 1, 2, 3, 4, 5, 6, 6, 6} if (min_index1 == 0 && max_index2 == n - 1) { Console.Write( "Ascending with maximum" + " element = " + max_element); } // First occurrence of maximum element is at the // beginning of the array and the last occurrence // of the minimum element is at the end of the // array then the array is sorted in descending // For example, {6, 6, 6, 5, 4, 3, 2, 1, 1, 1} else if (min_index2 == n - 1 && max_index1 == 0) { Console.Write( "Descending with maximum" + " element = " + max_element); } // First occurrence of maximum element is equal // to the last occurrence of the minimum element + 1 // then the array is descending and rotated // For example, {3, 2, 1, 1, 1, 6, 6, 6, 5, 4} else if (max_index1 == min_index2 + 1) { Console.Write( "Descending rotated with " + "maximum element = " + max_element); } // First occurrence of minimum element is equal // to the last occurrence of the maximum element + 1 // then the array is ascending and rotated // For example, {4, 5, 6, 6, 6, 1, 1, 1, 2, 3} else { Console.Write( "Ascending rotated with " + "maximum element = " + max_element); } } // Driver code static public void Main () { int []arr = { 4, 5, 6, 6, 6, 1, 1, 1, 2, 3 }; int n = arr.Length; findType(arr, n); } } // This code is contributed by ajit. |
Javascript
<script> // Javascript implementation of the approach // Function to find the type of an array // and maximum element in it function findType(arr, n) { // To store the minimum and the maximum // element from the array let min_element = Number.MAX_VALUE, max_element = Number.MIN_VALUE; // To store the first and the last occurrences // of the minimum and the maximum // element from the array let min_index1 = -1, max_index1 = -1, max_index2 = -1, min_index2 = -1; for (let i = 0; i < n; i++) { // If new minimum is found if (arr[i] < min_element) { // Update the minimum so far // and its occurrences min_element = arr[i]; min_index1 = i; min_index2 = i; } // If current element is equal the found // minimum so far then update the last // occurrence of the minimum element else if (arr[i] == min_element) min_index2 = i; // If new maximum is found if (arr[i] > max_element) { // Update the maximum so far // and its occurrences max_element = arr[i]; max_index1 = i; max_index2 = i; } // If current element is equal the found // maximum so far then update the last // occurrence of the maximum element else if (arr[i] == max_element) max_index2 = i; } // First occurrence of minimum element is at the // beginning of the array and the last occurrence // of the maximum element is at the end of the // array then the array is sorted in ascending // For example, {1, 1, 1, 2, 3, 4, 5, 6, 6, 6} if (min_index1 == 0 && max_index2 == n - 1) { document.write( "Ascending with maximum" + " element = " + max_element); } // First occurrence of maximum element is at the // beginning of the array and the last occurrence // of the minimum element is at the end of the // array then the array is sorted in descending // For example, {6, 6, 6, 5, 4, 3, 2, 1, 1, 1} else if (min_index2 == n - 1 && max_index1 == 0) { document.write( "Descending with maximum" + " element = " + max_element); } // First occurrence of maximum element is equal // to the last occurrence of the minimum element + 1 // then the array is descending and rotated // For example, {3, 2, 1, 1, 1, 6, 6, 6, 5, 4} else if (max_index1 == min_index2 + 1) { document.write( "Descending rotated with " + "maximum element = " + max_element); } // First occurrence of minimum element is equal // to the last occurrence of the maximum element + 1 // then the array is ascending and rotated // For example, {4, 5, 6, 6, 6, 1, 1, 1, 2, 3} else { document.write( "Ascending rotated with " + "maximum element = " + max_element); } } let arr = [ 4, 5, 6, 6, 6, 1, 1, 1, 2, 3 ]; let n = arr.length; findType(arr, n); </script> |
输出:
Ascending rotated with maximum element = 6
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