如何计算PHP中两个日期之间的差异？-yiteyi-C++库

在本文中，我们将看到如何在PHP中计算两个日期之间的差异，并通过示例了解其实现。给定两个日期，即开始日期和结束日期&我们需要找出这两个日期之间的差异。

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考虑下面的例子：

Input: start_date: 2016-06-01 22:45:00        end_date: 2018-09-21 10:44:01Output: 2 years, 3 months, 21 days, 11 hours, 59 minutes, 1 secondsExplanation: The difference of 2 dates will give the date in complete format.

方法1： 使用 date_diff（）函数

此函数用于查找两个日期之间的差异。此函数将在成功时返回DateInterval对象，在失败时返回FALSE。

实例：此示例说明如何使用date_diff（）函数计算两个日期之间的差异。

PHP

                         <?php                       
           
                                                 // Creates DateTime objects                       
                                                 $datetime1                                     = date_create(                                     '2016-06-01'                                     );                       
                                                 $datetime2                                     = date_create(                                     '2018-09-21'                                     );                       
           
                                                 // Calculates the difference between DateTime objects                       
                                                 $interval                                     = date_diff(                                     $datetime1                                     ,                                     $datetime2                                     );                       
           
                                                 // Printing result in years & months format                       
                                                 echo                                     $interval                                     ->format(                                     '%R%y years %m months'                                     );                       
                         ?>                       

输出：

+2 years 3 months

方法2： 使用日期-时间数学公式找出两个日期之间的差异。它返回两个指定日期之间的年、月、日、时、分、秒。

例子： 在本例中，我们将使用日期-时间数学公式计算以年、月、日、时、分、秒为单位返回的日期之间的差异。

PHP

                         <?php                       
           
                                                 // Declare and define two dates                       
                                                 $date1                                     =                                     strtotime                                     (                                     "2016-06-01 22:45:00"                                     );                       
                                                 $date2                                     =                                     strtotime                                     (                                     "2018-09-21 10:44:01"                                     );                       
           
                                                 // Formulate the Difference between two dates                       
                                                 $diff                                     =                                     abs                                     (                                     $date2                                     -                                     $date1                                     );                       
           
                                                 // To get the year divide the resultant date into                       
                                                 // total seconds in a year (365*60*60*24)                       
                                                 $years                                     =                                     floor                                     (                                     $diff                                     / (365*60*60*24));                       
           
                                                 // To get the month, subtract it with years and                       
                                                 // divide the resultant date into                       
                                                 // total seconds in a month (30*60*60*24)                       
                                                 $months                                     =                                     floor                                     ((                                     $diff                                     -                                     $years                                     * 365*60*60*24)                       
                                                 / (30*60*60*24));                       
           
                                                 // To get the day, subtract it with years and                       
                                                 // months and divide the resultant date into                       
                                                 // total seconds in a days (60*60*24)                       
                                                 $days                                     =                                     floor                                     ((                                     $diff                                     -                                     $years                                     * 365*60*60*24 -                       
                                                 $months                                     *30*60*60*24)/ (60*60*24));                       
           
                                                 // To get the hour, subtract it with years,                       
                                                 // months & seconds and divide the resultant                       
                                                 // date into total seconds in a hours (60*60)                       
                                                 $hours                                     =                                     floor                                     ((                                     $diff                                     -                                     $years                                     * 365*60*60*24                       
                                                 -                                     $months                                     *30*60*60*24 -                                     $days                                     *60*60*24)                       
                                                 / (60*60));                       
           
                                                 // To get the minutes, subtract it with years,                       
                                                 // months, seconds and hours and divide the                       
                                                 // resultant date into total seconds i.e. 60                       
                                                 $minutes                                     =                                     floor                                     ((                                     $diff                                     -                                     $years                                     * 365*60*60*24                       
                                                 -                                     $months                                     *30*60*60*24 -                                     $days                                     *60*60*24                       
                                                 -                                     $hours                                     *60*60)/ 60);                       
           
                                                 // To get the minutes, subtract it with years,                       
                                                 // months, seconds, hours and minutes                       
                                                 $seconds                                     =                                     floor                                     ((                                     $diff                                     -                                     $years                                     * 365*60*60*24                       
                                                 -                                     $months                                     *30*60*60*24 -                                     $days                                     *60*60*24                       
                                                 -                                     $hours                                     *60*60 -                                     $minutes                                     *60));                       
           
                                                 // Print the result                       
                                                 printf(                                     "%d years, %d months, %d days, %d hours, "                       
                                                 .                                     "%d minutes, %d seconds"                                     ,                                     $years                                     ,                                     $months                                     ,                       
                                                 $days                                     ,                                     $hours                                     ,                                     $minutes                                     ,                                     $seconds                                     );                       
                         ?>                       

输出：

2 years, 3 months, 21 days, 11 hours, 59 minutes, 1 seconds

方法3： 此方法用于获取两个指定日期之间的总天数。

PHP

                         <?php                       
           
                                                 // Declare two dates                       
                                                 $start_date                                     =                                     strtotime                                     (                                     "2018-06-08"                                     );                       
                                                 $end_date                                     =                                     strtotime                                     (                                     "2018-09-19"                                     );                       
           
                                                 // Get the difference and divide into                       
                                                 // total no. seconds 60/60/24 to get                       
                                                 // number of days                       
                                                 echo                                     "Difference between two dates: "                       
                                                 . (                                     $end_date                                     -                                     $start_date                                     )/60/60/24;                       
                         ?>                       

输出：

Difference between two dates: 103

PHP是一种专门为web开发设计的服务器端脚本语言。通过以下步骤，您可以从头开始学习PHP PHP的教程和 PHP示例 .

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