这个 pollFirst() 方法 LinkedBlockingDeque 返回Deque容器中的front元素,并将其删除。它回来了 无效的 如果容器是空的。
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语法:
public E pollFirst()
参数: 此方法不接受任何参数。
返回: 此方法返回 前元素 如果容器不是空的,则在Deque容器中删除该元素。它回来了 无效的 如果容器是空的。
下面的程序演示了LinkedBlockingDeque的pollFirst()方法:
项目1:
// Java Program Demonstrate pollFirst() // method of LinkedBlockingDeque import java.util.concurrent.LinkedBlockingDeque; import java.util.*; public class GFG { public static void main(String[] args) { // create object of LinkedBlockingDeque LinkedBlockingDeque<Integer> LBD = new LinkedBlockingDeque<Integer>(); // Add numbers to end of LinkedBlockingDeque LBD.addFirst( 7855642 ); LBD.addFirst( 35658786 ); LBD.addFirst( 5278367 ); LBD.addFirst( 74381793 ); // Print the queue System.out.println( "Linked Blocking Deque: " + LBD); // prints and deletes System.out.println( "Front element in Deque: " + LBD.pollFirst()); // Deque after deletion of front element System.out.println( "Linked Blocking Deque: " + LBD); } } |
输出:
Linked Blocking Deque: [74381793, 5278367, 35658786, 7855642] Front element in Deque: 74381793 Linked Blocking Deque: [5278367, 35658786, 7855642]
项目2:
// Java Program Demonstrate pollFirst() // method of LinkedBlockingDeque // when Deque is empty import java.util.concurrent.LinkedBlockingDeque; import java.util.*; public class GFG { public static void main(String[] args) { // create object of LinkedBlockingDeque LinkedBlockingDeque<Integer> LBD = new LinkedBlockingDeque<Integer>(); // Add numbers to end of LinkedBlockingDeque LBD.add( 7855642 ); LBD.add( 35658786 ); LBD.add( 5278367 ); LBD.add( 74381793 ); // Print the queue System.out.println( "Linked Blocking Deque: " + LBD); // empty deque LBD.clear(); System.out.println( "Front element in Deque: " + LBD.pollFirst()); } } |
输出:
Linked Blocking Deque: [7855642, 35658786, 5278367, 74381793] Front element in Deque: null
参考: https://docs.oracle.com/javase/7/docs/api/java/util/concurrent/LinkedBlockingDeque.html#pollFirst()
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