这个 peek last() 方法 LinkedBlockingDeque 返回Deque容器中的最后一个元素,但不删除它。它回来了 无效的 如果容器是空的。
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语法:
public E peekLast()
参数: 此方法不接受任何参数。
返回: 此方法返回 最后一个元素 如果容器不是空的,在Deque容器中。如果容器为空,则返回false。
下面的程序演示了LinkedBlockingDeque的peekLast()方法:
项目1:
// Java Program Demonstrate peekLast() // method of LinkedBlockingDeque import java.util.concurrent.LinkedBlockingDeque; import java.util.*; public class GFG { public static void main(String[] args) { // create object of LinkedBlockingDeque LinkedBlockingDeque<Integer> LBD = new LinkedBlockingDeque<Integer>(); // Add numbers to end of LinkedBlockingDeque LBD.addFirst( 7855642 ); LBD.addFirst( 35658786 ); LBD.addFirst( 5278367 ); LBD.addFirst( 74381793 ); // Print the queue System.out.println( "Linked Blocking Deque: " + LBD); System.out.println( "Front element in Deque: " + LBD.peekLast()); } } |
输出:
Linked Blocking Deque: [74381793, 5278367, 35658786, 7855642] Front element in Deque: 7855642
项目2:
// Java Program Demonstrate peekLast() // method of LinkedBlockingDeque // when Deque is empty import java.util.concurrent.LinkedBlockingDeque; import java.util.*; public class GFG { public static void main(String[] args) { // create object of LinkedBlockingDeque LinkedBlockingDeque<Integer> LBD = new LinkedBlockingDeque<Integer>(); // Add numbers to end of LinkedBlockingDeque LBD.add( 7855642 ); LBD.add( 35658786 ); LBD.add( 5278367 ); LBD.add( 74381793 ); // Print the queue System.out.println( "Linked Blocking Deque: " + LBD); // empty deque LBD.clear(); System.out.println( "Front element in Deque: " + LBD.peekLast()); } } |
输出:
Linked Blocking Deque: [7855642, 35658786, 5278367, 74381793] Front element in Deque: null
参考: https://docs.oracle.com/javase/7/docs/api/java/util/concurrent/LinkedBlockingDeque.html#peekLast()
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