这个 getFirst() 方法 LinkedBlockingDeque 返回Deque容器中最前面的元素。如果LinkedBlockingDeque为空,则在函数调用时返回 非接触性异常 .
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语法:
public E getLast()
参数: 此方法不接受任何参数。
返回: 此方法返回此Deque容器的第一个元素或头。
例外情况: 该函数只引发一个异常,即:。, 非接触性异常 当deque是空的
下面的程序演示了LinkedBlockingDeque的getFirst()方法:
项目1:
// Java Program Demonstrate getFirst() // method of LinkedBlockingDeque import java.util.concurrent.LinkedBlockingDeque; import java.util.*; public class GFG { public static void main(String[] args) throws IllegalStateException { // create object of LinkedBlockingDeque LinkedBlockingDeque<Integer> LBD = new LinkedBlockingDeque<Integer>(); // Add numbers to front of LinkedBlockingDeque LBD.addFirst( 7855642 ); LBD.addFirst( 35658786 ); LBD.addFirst( 5278367 ); LBD.addFirst( 74381793 ); // before removing print queue System.out.println( "Linked Blocking Deque: " + LBD); // prints the first element System.out.println( "Linked Blocking Deque first element: " + LBD.getFirst()); } } |
输出:
Linked Blocking Deque: [74381793, 5278367, 35658786, 7855642] Linked Blocking Deque first element: 74381793
项目2:
// Java Program Demonstrate getFirst() // method of LinkedBlockingDeque import java.util.concurrent.LinkedBlockingDeque; import java.util.*; public class GFG { public static void main(String[] args) throws IllegalStateException { // create object of LinkedBlockingDeque LinkedBlockingDeque<Integer> LBD = new LinkedBlockingDeque<Integer>(); // Add numbers to front of LinkedBlockingDeque LBD.addFirst( 7855642 ); LBD.addFirst( 35658786 ); LBD.addFirst( 5278367 ); LBD.addFirst( 74381793 ) LBD.clear(); // Since the container is empty it will throw exception System.out.println( "Linked Blocking Deque first element: " + LBD.getFirst()); } } |
输出:
Exception in thread "main" java.util.NoSuchElementException at java.util.concurrent.LinkedBlockingDeque.getFirst(LinkedBlockingDeque.java:553) at GFG.main(GFG.java:28)
参考: https://docs.oracle.com/javase/7/docs/api/java/util/concurrent/LinkedBlockingDeque.html#getFirst()
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