jdtofrench()函数是一个内置函数,用于转换 朱利安日整数 到 法国约会。 该函数接受一个儒略日整数,并返回转换后的法语日期 $month/$day/$year。
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语法:
jdtofrench($jd)
参数: 该函数接受一个强制参数 $jd 它指定了朱利安日。
返回值: 函数返回法国日期。日期的返回格式为 $month/$day/$year。 如果Julian day整数被传递为0,那么0/0/0将作为输出返回。
例如:
Input : 2379254 Output : 5/8/10 Input : 2380229 Output : 1/7/13
下面的程序演示了jdtofrench()函数。
项目1: 下面的程序演示了jdtofrench()函数的用法。
<?php // PHP program to demonstrate the // use of jdtofrench() function // converts date to julian integer $jd = frenchtojd(1, 7, 13); // prints the julian day integer echo "The julian day integer is " , $jd , "" ; // converts the Julian day to French date $date = jdtofrench( $jd ); // prints the date echo "The french date initially taken was " , ( $date ), "" ; ?> |
输出:
The julian day integer is 2380229 The french date initially taken was 1/7/13
项目2: 下面的程序显示了传递无效的Julian day整数时的输出。
<?php // PHP program to demonstrate the // use of jdtofrench() function // in case of out of range parameter is passed // converts date to julian integer $jd = frenchtojd(1, 7, 18); // prints the julian day integer as 0 as year is out of range echo "The julian day integer is " , $jd , "" ; // converts the Julian day to French date $date = jdtofrench( $jd ); // prints the date as 0/0/0 as french year is out of range echo "The french date initially taken was " , ( $date ), "" ; ?> |
输出:
The julian day integer is 0 The french date initially taken was 0/0/0
参考: http://php.net/manual/en/function.jdtofrench.php
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