Java中的DoubleStream mapToLong()

DoubleStream mapToLong() 返回一个长流,其中包含将给定函数应用于该流元素的结果。

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注: DoubleStream mapToLong()是一个 中间操作。 这些操作总是懒惰的。在流实例上调用中间操作,完成处理后,它们将流实例作为输出。 语法:

LongStream mapToLong(DoubleToLongFunction mapper)

参数:

  1. 双流: 一个原始的双值元素序列。这是人类的双重本原特化 流动 .
  2. 制图员: 应用于每个元素的无状态函数。

返回值: 该函数返回一个长流,其中包含将给定函数应用于该流元素的结果。

例1:

// Java code for LongStream mapToLong
// (DoubleToLongFunction mapper)
import java.util.*;
import java.util.stream.LongStream;
import java.util.stream.DoubleStream;
class GFG {
// Driver code
public static void main(String[] args)
{
// Creating a DoubleStream
DoubleStream stream = DoubleStream.of( 3.3 , 6.5 , 16.4 ,
8.7 , 10.4 );
// Using LongStream mapToLong(DoubleToLongFunction mapper)
// to return a LongStream consisting of the
// results of applying the given function to
// the elements of this stream.
LongStream stream1 = stream.mapToLong(num -> ( long )num);
// Displaying the elements in stream1
stream1.forEach(System.out::println);
}
}


输出:

3
6
16
8
10

例2:

// Java code for LongStream mapToLong
// (DoubleToLongFunction mapper)
import java.util.*;
import java.util.stream.LongStream;
import java.util.stream.DoubleStream;
class GFG {
// Driver code
public static void main(String[] args)
{
// Creating a DoubleStream
DoubleStream stream = DoubleStream.of( 3.3 , 6.5 , 16.4 ,
8.7 , 10.4 );
// Using LongStream mapToLong(DoubleToLongFunction mapper)
// to return a LongStream consisting of the
// results of applying the given function to
// the elements of this stream.
LongStream stream1 = stream.mapToLong(num -> ( long )num - 10 );
// Displaying the elements in stream1
stream1.forEach(System.out::println);
}
}


输出:

-7
-4
6
-2
0

例3:

// Java code for LongStream mapToLong
// (DoubleToLongFunction mapper)
import java.util.*;
import java.util.stream.LongStream;
import java.util.stream.DoubleStream;
class GFG {
// Driver code
public static void main(String[] args)
{
// Creating a DoubleStream
DoubleStream stream = DoubleStream.of( 3.3 , 6.5 , 16.4 ,
8.7 , 10.4 );
// Using LongStream mapToLong(DoubleToLongFunction mapper)
// to return a LongStream consisting of the
// results of applying the given function to
// the elements of this stream.
LongStream stream1 = stream.mapToLong(num -> ( long )( 2 * num * num));
// Displaying the elements in stream1
stream1.forEach(System.out::println);
}
}


输出:

21
84
537
151
216
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