Python中的hex（）函数-yiteyi-C++库

十六进制（） 函数是Python3中的内置函数之一，用于将整数转换为对应的十六进制形式。

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语法：

hex(x) Parameters : x - an integer number (int object)Returns :  Returns hexadecimal string.

错误和例外：

TypeError :  Returns TypeError when anything other than             integer type constants are passed as parameters.

代码#1： 说明了 十六进制（） 作用

Python3

                         # Python3 program to illustrate                       
                         # hex() function                       
           
                         print                                     (                                     "The hexadecimal form of 23 is "                       
                                                 +                                     hex                                     (                                     23                                     ))                       
                                   
                         print                                     (                                     "The hexadecimal form of the "                       
                                                 "ascii value is 'a' is "                                     +                                     hex                                     (                                     ord                                     (                                     'a'                                     )))                       
                                   
                         print                                     (                                     "The hexadecimal form of 3.9 is "                       
                                                 +                                     float                                     .                                     hex                                     (                                     3.9                                     ))                       

输出：

The hexadecimal form of 23 is 0x17The hexadecimal form of the ascii value os 'a' is 0x61The hexadecimal form of 3.9 is 0x1.f333333333333p+1

代码#2： 演示浮点值作为参数传递时的TypeError。

Python3

                         # hex() accepts only integer values as parameters                       
                         print                                     (                                     "The hexadecimal form of 11.1 is "                       
                                                 +                                     hex                                     (                                     11.1                                     ))                       
           
                         '''                       
                         # The hexadecimal conversion of floating                       
                         # point integers can be done using the                       
                         # function float.hex()                       
                         print("The hexadecimal form of 11.1 is "                       
                                                 + float.hex(11.1))                       
                         # Output :                       
                         # The hexadecimal form of 11.1 is 0x1.6333333333333p+3                       
           
                         # Similarly, float.hex() throws a TypeError                       
                         # when integer values are passed in it.                       
                         '''                       

输出：

Traceback (most recent call last):  File "/home/7e1ac7e34362fd690cdb72cf294502e1.py", line 2, in     print("The hexadecimal form of 11.1 is "+hex(11.1))TypeError: 'float' object cannot be interpreted as an integer

应用： hex（）用于所有 标准转换 .例如，十六进制到十进制、十六进制到八进制、十六进制到二进制的转换。

代码#3：

Python3

                         # TypeConversion from decimal with base 10                       
                         # to hexadecimal form with base 16                       
           
           
                         # Taking input from user                       
                         # an integer with base 10                       
                         number                                     =                                     int                                     (                                     input                                     (                                     "Enter a number with base 10"                                     ))                       
           
                         # The choices present to the user                       
                         print                                     (                                     "a. Decimal to Hexadecimal "                                     )                       
                         print                                     (                                     "b. Decimal to Octal"                                     )                       
                         print                                     (                                     "c. Decimal to Binary"                                     )                       
           
                         # taking user input                       
                         print                                     (                                     "Enter your choice :- "                                     )                       
                         choice                                     =                                     input                                     ()                       
           
                         # Running a variable choice                       
                         # Hexadecimal form if choice                       
                         # is set to 'a'                       
                         if                                     choice                                     is                                     'a'                                     :                       
           
                                                 # lstrip helps remove "0x" from the left                       
                                                 # rstrip helps remove "L" from the right,                       
                                                 # L represents a long number                       
                                                 print                                     (                                     "Hexadecimal form of "                                     +                                     str                                     (number)                                     +                       
                                                 " is "                                     +                                     hex                                     (number).lstrip(                                     "0x"                                     ).rstrip(                                     "L"                                     ))                       
                                   
                         if                                     choice                                     is                                     'b'                                     :                       
                                   
                                                 # Octal representation is done                       
                                                 # by adding a prefix "0o"                       
                                                 print                                     (                                     "Octal form of "                                     +                                     str                                     (number)                                     +                       
                                                 " is "                                     +                                     oct                                     (number).lstrip(                                     "0o"                                     ).rstrip(                                     "L"                                     ))                       
                                   
                         if                                     choice                                     is                                     'c'                                     :                       
                                   
                                                 # Binary representation is done by                       
                                                 # the addition of prefix "0b"                       
                                                 print                                     (                                     "Binary form of "                                     +                                     str                                     (number)                                     +                       
                                                 " is "                                     +                                     bin                                     (number).lstrip(                                     "0b"                                     ).rstrip(                                     "L"                                     ))                       

输出：

输入变量a）

Enter a number with base 10123a. Decimal to Hexadecimal b. Decimal to Octalc. Decimal to BinaryEnter your choice:- aHexadecimal form of 123 is 7b

输入变量b）

Enter a number with base 10123456789a. Decimal to Hexadecimal b. Decimal to Octalc. Decimal to BinaryEnter your choice:- aHexadecimal form of 123456789 is 75bcd15

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