Java中的IntStream findFirst()

IntStream findFirst() 返回一个 可选的 (可能包含也可能不包含非空值的容器对象)描述 第一 元素,如果流为空,则为空选项

null

语法:

OptionalInt findFirst()

Where, OptionalInt is a container object which
may or may not contain a non-null value 
and the function returns an OptionalInt describing the 
first element of this stream, or an empty OptionalInt
if the stream is empty. 

注: findFirst()是一个 终端短路 流接口的操作。此方法返回满足中间操作的任何第一个元素。

例1: 整数流上的findFirst()方法。

// Java code for IntStream findFirst()
// which returns an OptionalInt describing
// first element of the stream, or an
// empty OptionalInt if the stream is empty.
import java.util.*;
import java.util.stream.IntStream;
class GFG {
// Driver code
public static void main(String[] args)
{
// Creating an IntStream
IntStream stream = IntStream.of( 6 , 7 , 8 , 9 );
// Using IntStream findFirst() to return
// an OptionalInt describing first element
// of the stream
OptionalInt answer = stream.findFirst();
// if the stream is empty, an empty
// OptionalInt is returned.
if (answer.isPresent())
System.out.println(answer.getAsInt());
else
System.out.println( "no value" );
}
}


输出:

6

注: 如果流没有遭遇顺序,那么可以返回任何元素。

例2: 方法返回可被4整除的第一个元素。

// Java code for IntStream findFirst()
// which returns an OptionalInt describing
// first element of the stream, or an
// empty OptionalInt if the stream is empty.
import java.util.OptionalInt;
import java.util.stream.IntStream;
class GFG {
// Driver code
public static void main(String[] args)
{
// Creating an IntStream
IntStream stream = IntStream.of( 4 , 5 , 8 , 10 , 12 , 16 )
.parallel();
// Using IntStream findFirst().
// Executing the source code multiple times
// must return the same result.
// Every time you will get the same
// Integer which is divisible by 4.
stream = stream.filter(num -> num % 4 == 0 );
OptionalInt answer = stream.findFirst();
if (answer.isPresent())
System.out.println(answer.getAsInt());
}
}


输出:

4
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