IntStream findFirst() 返回一个 可选的 (可能包含也可能不包含非空值的容器对象)描述 第一 元素,如果流为空,则为空选项
null
语法:
OptionalInt findFirst() Where, OptionalInt is a container object which may or may not contain a non-null value and the function returns an OptionalInt describing the first element of this stream, or an empty OptionalInt if the stream is empty.
注: findFirst()是一个 终端短路 流接口的操作。此方法返回满足中间操作的任何第一个元素。
例1: 整数流上的findFirst()方法。
// Java code for IntStream findFirst() // which returns an OptionalInt describing // first element of the stream, or an // empty OptionalInt if the stream is empty. import java.util.*; import java.util.stream.IntStream; class GFG { // Driver code public static void main(String[] args) { // Creating an IntStream IntStream stream = IntStream.of( 6 , 7 , 8 , 9 ); // Using IntStream findFirst() to return // an OptionalInt describing first element // of the stream OptionalInt answer = stream.findFirst(); // if the stream is empty, an empty // OptionalInt is returned. if (answer.isPresent()) System.out.println(answer.getAsInt()); else System.out.println( "no value" ); } } |
输出:
6
注: 如果流没有遭遇顺序,那么可以返回任何元素。
例2: 方法返回可被4整除的第一个元素。
// Java code for IntStream findFirst() // which returns an OptionalInt describing // first element of the stream, or an // empty OptionalInt if the stream is empty. import java.util.OptionalInt; import java.util.stream.IntStream; class GFG { // Driver code public static void main(String[] args) { // Creating an IntStream IntStream stream = IntStream.of( 4 , 5 , 8 , 10 , 12 , 16 ) .parallel(); // Using IntStream findFirst(). // Executing the source code multiple times // must return the same result. // Every time you will get the same // Integer which is divisible by 4. stream = stream.filter(num -> num % 4 == 0 ); OptionalInt answer = stream.findFirst(); if (answer.isPresent()) System.out.println(answer.getAsInt()); } } |
输出:
4
© 版权声明
文章版权归作者所有,未经允许请勿转载。
THE END