Python |集合中的remove()和discard()

在本文中,我们将看到如何使用discard()和remove()方法删除集合中的元素。我们还将了解这两种方法之间的差异,尽管它们产生相同的结果。

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例如:

Input : set = ([10, 20, 26, 41, 54, 20])
Output : {41, 10, 26, 54}

Input : set = (["ram", "aakash", "kaushik", "anand", "prashant"])
Output : {'ram', 'prashant', 'kaushik', 'anand'}

方法1:使用discard()方法

Python中的内置方法discard()仅当元素存在于集合中时才从集合中移除该元素。如果元素不在集合中,则不会引发错误或异常,并打印原始集合。 如果元素存在于集合中:

# Python program to remove random elements of choice
# Function to remove elements using discard()
def Remove(sets):
sets.discard( 20 )
print (sets)
# Driver Code
sets = set ([ 10 , 20 , 26 , 41 , 54 , 20 ])
Remove(sets)


输出:

{41, 10, 26, 54}

如果该元素不在集合中:

# Python program to remove random elements of choice
# Function to remove elements using discard()
def Remove(sets):
sets.discard( 21 )
print (sets)
# Driver Code
sets = set ([ 10 , 20 , 26 , 41 , 54 , 20 ])
Remove(sets)


输出:

{41, 10, 26, 20, 54}

方法2:使用remove()方法

Python中的内置方法remove()仅当元素存在于集合中时才从集合中移除元素,就像discard()方法一样,但如果元素不存在于集合中,则会引发错误或异常。 如果元素存在于集合中:

# Python program to remove random elements of choice
# Function to remove elements using remove()
def Remove(sets):
sets.remove( "aakash" )
print (sets)
# Driver Code
sets = set ([ "ram" , "aakash" , "kaushik" , "anand" , "prashant" ])
Remove(sets)


输出:

{'ram', 'anand', 'prashant', 'kaushik'}

如果该元素不在集合中:

# Python program to remove random elements of choice
# Function to remove elements using remove()
def Remove(sets):
sets.remove( "gaurav" )
print (sets)
# Driver Code
sets = set ([ "ram" , "aakash" , "kaushik" , "anand" , "prashant" ])
Remove(sets)


输出:

No Output

错误:

Traceback (most recent call last):
  File "/home/bf95b32da22ada77d72062a73d3e0980.py", line 9, in 
    Remove(sets)
  File "/home/bf95b32da22ada77d72062a73d3e0980.py", line 4, in Remove
    sets.remove("gaurav")
KeyError: 'gaurav'
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