两个浮点数或双数的模-yiteyi-C++库

给定两个浮点数，求余数。

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例如：

输入：a=36.5，b=5.0 输出： 1.5

输入： a=9.7，b=2.3 输出： 0.5

建议：请在“上解决” 实践 “首先，在讨论解决方案之前。

A. 简单解决方案 就是重复减法。

C++

                         // C++ program to find modulo of floating                       
                         // point numbers.                       
                         #include <bits/stdc++.h>                       
                         using                                     namespace                                     std;                       
           
                         double                                     findMod(                                     double                                     a,                                     double                                     b)                       
                         {                       
                                                 double                                     mod;                       
                                                 // Handling negative values                       
                                                 if                                     (a < 0)                       
                                                 mod = -a;                       
                                                 else                       
                                                 mod =  a;                       
                                                 if                                     (b < 0)                       
                                                 b = -b;                       
           
                                                 // Finding mod by repeated subtraction                       
                                   
                                                 while                                     (mod >= b)                       
                                                 mod = mod - b;                       
           
                                                 // Sign of result typically depends                       
                                                 // on sign of a.                       
                                                 if                                     (a < 0)                       
                                                 return                                     -mod;                       
           
                                                 return                                     mod;                       
                         }                       
           
                         // Driver Function                       
                         int                                     main()                       
                         {                       
                                                 double                                     a = 9.7, b = 2.3;                       
                                                 cout << findMod(a, b);                       
                                                 return                                     0;                       
                         }                       

JAVA

                         // Java program to find modulo of floating                       
                         // point numbers                       
           
                         class                                     GFG                       
                         {                       
                                                 static                                     double                                     findMod(                                     double                                     a,                                     double                                     b)                       
                                                 {                       
                                                 // Handling negative values                       
                                                 if                                     (a <                                     0                                     )                       
                                                 a = -a;                       
                                                 if                                     (b <                                     0                                     )                       
                                                 b = -b;                       
                                   
                                                 // Finding mod by repeated subtraction                       
                                                 double                                     mod = a;                       
                                                 while                                     (mod >= b)                       
                                                 mod = mod - b;                       
                                   
                                                 // Sign of result typically depends                       
                                                 // on sign of a.                       
                                                 if                                     (a <                                     0                                     )                       
                                                 return                                     -mod;                       
                                   
                                                 return                                     mod;                       
                                                 }                       
                                   
                                                 // Driver code                       
                                                 public                                     static                                     void                                     main (String[] args)                       
                                                 {                       
                                                 double                                     a =                                     9.7                                     , b =                                     2.3                                     ;                       
                                                 System.out.print(findMod(a, b));                       
                                                 }                       
                         }                       
           
                         // This code is contributed by Anant Agarwal.                       

Python3

                         # Python3 program to find modulo                       
                         # of floating point numbers.                       
           
                         def                                     findMod(a, b):                       
           
                                                 # Handling negative values                       
                                                 if                                     (a <                                     0                                     ):                       
                                                 a                                     =                                     -                                     a                       
                                                 if                                     (b <                                     0                                     ):                       
                                                 b                                     =                                     -                                     b                       
           
                                                 # Finding mod by repeated subtraction                       
                                                 mod                                     =                                     a                       
                                                 while                                     (mod >                                     =                                     b):                       
                                                 mod                                     =                                     mod                                     -                                     b                       
           
                                                 # Sign of result typically                       
                                                 # depends on sign of a.                       
                                                 if                                     (a <                                     0                                     ):                       
                                                 return                                     -                                     mod                       
           
                                                 return                                     mod                       
           
                         # Driver code                       
                         a                                     =                                     9.7                                     ; b                                     =                                     2.3                       
                         print                                     (findMod(a, b))                       
           
                         # This code is contributed by Anant Agarwal.                       

C#

                         // C# program to find modulo of floating                       
                         // point numbers                       
                         using                                     System;                       
           
                         class                                     GFG {                       
                                   
                                                 static                                     double                                     findMod(                                     double                                     a,                                     double                                     b)                       
                                                 {                       
                                   
                                                 // Handling negative values                       
                                                 if                                     (a < 0)                       
                                                 a = -a;                       
                                                 if                                     (b < 0)                       
                                                 b = -b;                       
                                   
                                                 // Finding mod by repeated subtraction                       
                                                 double                                     mod = a;                       
                                                 while                                     (mod >= b)                       
                                                 mod = mod - b;                       
                                   
                                                 // Sign of result typically depends                       
                                                 // on sign of a.                       
                                                 if                                     (a < 0)                       
                                                 return                                     -mod;                       
                                   
                                                 return                                     mod;                       
                                                 }                       
                                   
                                                 // Driver code                       
                                                 public                                     static                                     void                                     Main ()                       
                                                 {                       
                                   
                                                 double                                     a = 9.7, b = 2.3;                       
                                   
                                                 Console.WriteLine(findMod(a, b));                       
                                                 }                       
                         }                       
           
                         // This code is contributed by vt_m.                       

PHP

                         <?php                       
                         // PHP program to find modulo                       
                         // of floatingpoint numbers.                       
           
                         function                                     findMod(                                     $a                                     ,                                     $b                                     )                       
                         {                       
                                   
                                                 // Handling negative values                       
                                                 if                                     (                                     $a                                     < 0)                       
                                                 $a                                     = -                                     $a                                     ;                       
                                                 if                                     (                                     $b                                     < 0)                       
                                                 $b                                     = -                                     $b                                     ;                       
           
                                                 // Finding mod by repeated                       
                                                 // subtraction                       
                                                 $mod                                     =                                     $a                                     ;                       
                                                 while                                     (                                     $mod                                     >=                                     $b                                     )                       
                                                 $mod                                     =                                     $mod                                     -                                     $b                                     ;                       
           
                                                 // Sign of result typically                       
                                                 // depends on sign of a.                       
                                                 if                                     (                                     $a                                     < 0)                       
                                                 return                                     -                                     $mod                                     ;                       
           
                                                 return                                     $mod                                     ;                       
                         }                       
           
                                                 // Driver Code                       
                                                 $a                                     = 9.7;                                     $b                                     = 2.3;                       
                                                 echo                                     findMod(                                     $a                                     ,                                     $b                                     );                       
                                   
                         // This code is contributed by anuj_65.                       
                         ?>                       

Javascript

                         <script>                       
           
                         // Javascript program to find                       
                         // modulo of floating point numbers.                       
           
                         function                                     findMod(a, b)                       
                         {                       
                                                 let mod;                       
                                                 // Handling negative values                       
                                                 if                                     (a < 0)                       
                                                 mod = -a;                       
                                                 else                       
                                                 mod =  a;                       
                                                 if                                     (b < 0)                       
                                                 b = -b;                       
           
                                                 // Finding mod by                       
                                                 // repeated subtraction                       
                                   
                                                 while                                     (mod >= b)                       
                                                 mod = mod - b;                       
           
                                                 // Sign of result typically                       
                                                 // depends on sign of a.                       
                                                 if                                     (a < 0)                       
                                                 return                                     -mod;                       
           
                                                 return                                     mod;                       
                         }                       
           
                         // Driver Function                       
           
                                                 let a = 9.7, b = 2.3;                       
                                                 document.write(findMod(a, b));                       
           
                         //This code is contributed by Mayank Tyagi                       
                         </script>                       

输出：

0.5

我们可以使用内置的 fmod函数求两个浮点数的模。

C++

                         // CPP program to find modulo of floating                       
                         // point numbers using library function.                       
                         #include <bits/stdc++.h>                       
                         using                                     namespace                                     std;                       
           
                         // Driver Function                       
                         int                                     main()                       
                         {                       
                                                 double                                     a = 9.7, b = 2.3;                       
                                                 cout <<                                     fmod                                     (a, b);                       
                                                 return                                     0;                       
                         }                       

JAVA

                         // JAVA program to find modulo of floating                       
                         // point numbers using library function.                       
                         import                                     java.util.*;                       
           
                         class                                     GFG{                       
           
                         // Driver Function                       
                         public                                     static                                     void                                     main(String[] args)                       
                         {                       
                                                 double                                     a =                                     9.7                                     , b =                                     2.3                                     ;                       
                                                 System.out.print((a % b));                       
                         }                       
                         }                       
           
                         // This code contributed by umadevi9616                       

Python3

                         # Python3 program to find modulo of floating                       
                         # point numbers using library function.                       
                         from                                     math                                     import                                     fmod                       
           
                         # Driver code                       
                         if                                     __name__                                     =                                     =                                     '__main__'                                     :                       
                                   
                                                 a                                     =                                     9.7                       
                                                 b                                     =                                     2.3                       
                                   
                                                 print                                     (fmod(a, b))                       
           
                         # This code is contributed by mohit kumar 29                       

C#

                         // C# program to find modulo of floating                       
                         // point numbers using library function.                       
                         using                                     System;                       
           
                         class                                     GFG{                       
                                   
                         static                                     void                                     Main()                       
                         {                       
                                                 double                                     a = 9.7;                       
                                                 double                                     b = 2.3;                       
                                                 Console.WriteLine(a % b);                       
                         }                       
                         }                       
           
                         // This code is contributed by mukesh07                       

PHP

                         <?php                       
                         // PHP program to find modulo of                       
                         // floating point numbers using                       
                         // library function.                       
           
                         // Driver Code                       
                         $a                                     = 9.7;                                     $b                                     = 2.3;                       
                         echo                                     fmod                                     (                                     $a                                     ,                                     $b                                     );                       
           
                         // This code is contributed                       
                         // by inder_verma                       
                         ?>                       

Javascript

                         <script>                       
           
                         // Javascript program to find modulo of                       
                         // floating point numbers using                       
                         // library function.                       
           
                         // Driver Code                       
                         let a = 9.7;                       
                         let b = 2.3;                       
                         document.write(a%b);                       
           
                         // This code is contributed by mohan pavan                       
           
                         </script>                       

输出：

0.5

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