Python中的循环冗余校验

先决条件: 了解循环冗余 , 套接字编程

null

什么是CRC? CRC或循环冗余校验是一种检测通信信道中意外变化/错误的方法。 CRC使用在发送方和接收方都可用的生成器多项式。示例生成器多项式的形式为x^3+1。该生成器多项式表示键1001。另一个例子是x^2+x,代表键110。

例子: 让数据发送是“EVN” 我们将字符串转换为二进制字符串数据。

python

input_string = "EVN"
# CONVERT string data to binary string data
data = (' '.join(format(ord(x), ' b') for x in input_string))
print (data)


输出

100010110101101001110

CRC密钥:1001 代码:CRC密钥长度-1->000追加在数据末尾。

New data: 100010110101101001110000Key:1001

现在,我们在套接字编程python的发送方和接收方都应用了CRC。

发送方

1.任务是向服务器/接收方发送字符串数据。 2.发送方发送一个字符串,让我们说“EVN”。 3.首先,将该字符串转换为二进制字符串“1000101101101001110”。发送方和接收方都知道密钥,此处使用的密钥为1001。 4.使用客户端/发送方的密钥,使用CRC代码对该数据进行编码。 5.该编码数据被发送到接收器。 6.接收器随后对编码的数据字符串进行解码,以验证是否存在任何错误。

Python3

# Import socket module
import socket
def xor(a, b):
# initialize result
result = []
# Traverse all bits, if bits are
# same, then XOR is 0, else 1
for i in range ( 1 , len (b)):
if a[i] = = b[i]:
result.append( '0' )
else :
result.append( '1' )
return ''.join(result)
# Performs Modulo-2 division
def mod2div(divident, divisor):
# Number of bits to be XORed at a time.
pick = len (divisor)
# Slicing the divident to appropriate
# length for particular step
tmp = divident[ 0 : pick]
while pick < len (divident):
if tmp[ 0 ] = = '1' :
# replace the divident by the result
# of XOR and pull 1 bit down
tmp = xor(divisor, tmp) + divident[pick]
else : # If leftmost bit is '0'
# If the leftmost bit of the dividend (or the
# part used in each step) is 0, the step cannot
# use the regular divisor; we need to use an
# all-0s divisor.
tmp = xor( '0' * pick, tmp) + divident[pick]
# increment pick to move further
pick + = 1
# For the last n bits, we have to carry it out
# normally as increased value of pick will cause
# Index Out of Bounds.
if tmp[ 0 ] = = '1' :
tmp = xor(divisor, tmp)
else :
tmp = xor( '0' * pick, tmp)
checkword = tmp
return checkword
# Function used at the sender side to encode
# data by appending remainder of modular division
# at the end of data.
def encodeData(data, key):
l_key = len (key)
# Appends n-1 zeroes at end of data
appended_data = data + '0' * (l_key - 1 )
remainder = mod2div(appended_data, key)
# Append remainder in the original data
codeword = data + remainder
return codeword
# Create a socket object
s = socket.socket()
# Define the port on which you want to connect
port = 12345
# connect to the server on local computer
s.connect(( '127.0.0.1' , port))
# Send data to server 'Hello world'
## s.sendall('Hello World')
input_string = input ( "Enter data you want to send->" )
#s.sendall(input_string)
data = (' '.join(format(ord(x), ' b') for x in input_string))
print ( "Entered data in binary format :" ,data)
key = "1001"
ans = encodeData(data,key)
print ( "Encoded data to be sent to server in binary format :" ,ans)
s.sendto(ans.encode(),( '127.0.0.1' , 12345 ))
# receive data from the server
print ( "Received feedback from server :" ,s.recv( 1024 ).decode())
# close the connection
s.close()


图片[1]-Python中的循环冗余校验-yiteyi-C++库

接收端

1.接收方从发送方接收编码数据字符串。 2.接收器在钥匙的帮助下解码数据并找出剩余部分。 3.如果余数为零,则表示发送方发送给接收方的数据没有错误。 4.如果余数为非零,则表示存在错误,将向发送方发送否定确认。然后发送方重新发送数据,直到接收方收到正确的数据。

Python3

# First of all import the socket library
import socket
def xor(a, b):
# initialize result
result = []
# Traverse all bits, if bits are
# same, then XOR is 0, else 1
for i in range ( 1 , len (b)):
if a[i] = = b[i]:
result.append( '0' )
else :
result.append( '1' )
return ''.join(result)
# Performs Modulo-2 division
def mod2div(divident, divisor):
# Number of bits to be XORed at a time.
pick = len (divisor)
# Slicing the divident to appropriate
# length for particular step
tmp = divident[ 0 : pick]
while pick < len (divident):
if tmp[ 0 ] = = '1' :
# replace the divident by the result
# of XOR and pull 1 bit down
tmp = xor(divisor, tmp) + divident[pick]
else : # If leftmost bit is '0'
# If the leftmost bit of the dividend (or the
# part used in each step) is 0, the step cannot
# use the regular divisor; we need to use an
# all-0s divisor.
tmp = xor( '0' * pick, tmp) + divident[pick]
# increment pick to move further
pick + = 1
# For the last n bits, we have to carry it out
# normally as increased value of pick will cause
# Index Out of Bounds.
if tmp[ 0 ] = = '1' :
tmp = xor(divisor, tmp)
else :
tmp = xor( '0' * pick, tmp)
checkword = tmp
return checkword
# Function used at the receiver side to decode
# data received by sender
def decodeData(data, key):
l_key = len (key)
# Appends n-1 zeroes at end of data
appended_data = data.decode() + '0' * (l_key - 1 )
remainder = mod2div(appended_data, key)
return remainder
# Creating Socket
s = socket.socket()
print ( "Socket successfully created" )
# reserve a port on your computer in our
# case it is 12345 but it can be anything
port = 12345
s.bind(('', port))
print ( "socket binded to %s" % (port))
# put the socket into listening mode
s.listen( 5 )
print ( "socket is listening" )
while True :
# Establish connection with client.
c, addr = s.accept()
print ( 'Got connection from' , addr)
# Get data from client
data = c.recv( 1024 )
print ( "Received encoded data in binary format :" , data.decode())
if not data:
break
key = "1001"
ans = decodeData(data, key)
print ( "Remainder after decoding is->" + ans)
# If remainder is all zeros then no error occured
temp = "0" * ( len (key) - 1 )
if ans = = temp:
c.sendto(( "THANK you Data ->" + data.decode() +
" Received No error FOUND" ).encode(), ( '127.0.0.1' , 12345 ))
else :
c.sendto(( "Error in data" ).encode(), ( '127.0.0.1' , 12345 ))
c.close()


OUTPUT

注: 如何运行该程序: 1.你应该有一个套接字编程库。

2.首先运行服务器程序,然后运行客户端程序。

3.复制粘贴代码时可能会出现缩进错误,因此复制时要小心。

4.您将在拆分终端中看到以下输出。

图片[3]-Python中的循环冗余校验-yiteyi-C++库

© 版权声明
THE END
喜欢就支持一下吧
点赞7 分享