这个 努比。伊斯南() 函数测试元素是否为NaN,并以布尔数组的形式返回结果。 语法:
null
numpy.isnan(array [, out])
参数:
array : [array_like]Input array or object whose elements, we need to test for infinity out : [ndarray, optional]Output array placed with result. Its type is preserved and it must be of the right shape to hold the output.
返回:
boolean array containing the result. For scalar input, the result is a new boolean with value True if the input is positive or negative infinity; otherwise the value is False. For array input, the result is a boolean array with the same shape as the input and the values are True where the corresponding element of the input is positive or negative infinity; elsewhere the values are False.
代码1:
# Python Program illustrating # numpy.isnan() method import numpy as geek print ( "Is NaN : " , geek.isnan( 1 ), "" ) print ( "Is NaN : " , geek.isnan( 0 ), "" ) # not a number print ( "Is NaN : " , geek.isnan(geek.nan), "" ) # infinity print ( "Is NaN : " , geek.isnan(geek.inf), "" ) print ( "Is NaN : " , geek.isnan(geek.NINF), "" ) x = geek.array([ - geek.inf, 0. , geek.inf]) y = geek.array([ 2 , 2 , 2 ]) print ( "Checking for NaN : " , geek.isnan(x, y)) |
输出:
Is NaN : False Is NaN : False Is NaN : True Is NaN : False Is NaN : False Checking for NaN : [0 0 0]
代码2:
# Python Program illustrating # numpy.isnan() method import numpy as geek # Returns True/False value for each element b = geek.arange( 20 ).reshape( 5 , 4 ) print ( "" ,b) print ( "Is NaN(Not a Number): " , geek.isnan(b)) b = [[ 1j ], [geek.nan]] print ( "Is NaN(Not a Number) : " , geek.isnan(b)) |
输出:
[[ 0 1 2 3] [ 4 5 6 7] [ 8 9 10 11] [12 13 14 15] [16 17 18 19]] Is NaN(Not a Number): [[False False False False] [False False False False] [False False False False] [False False False False] [False False False False]] Is NaN(Not a Number) : [[False] [ True]]
参考资料: https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.isnan.html
注: 这些代码不会在online-ID上运行。请在您的系统上运行它们以探索工作环境。 . 本文由 莫希特·古普塔(Mohit Gupta_OMG) .如果你喜欢GeekSforgek,并想贡献自己的力量,你也可以使用 贡献极客。组织 或者把你的文章寄到contribute@geeksforgeeks.org.看到你的文章出现在Geeksforgeks主页上,并帮助其他极客。
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