C++中的lambda表达式

C++ 11引入了lambda表达式,允许我们编写一个内联函数,它可以用于短代码片段,这些代码不会重用,不值得命名。lambda表达式的最简单形式可定义如下:

null
[ capture clause ] (parameters) -> return-type  {      definition of method   } 

通常,lambda表达式中的返回类型由编译器本身计算,我们不需要指定可以忽略显式的and->return type部分,但在一些复杂的情况下,如在条件语句中,编译器无法识别返回类型,我们需要指定它。 lambda表达式与标准函数的各种用途如下:

CPP

// C++ program to demonstrate lambda expression in C++
#include <bits/stdc++.h>
using namespace std;
// Function to print vector
void printVector(vector< int > v)
{
// lambda expression to print vector
for_each(v.begin(), v.end(), []( int i)
{
std::cout << i << " " ;
});
cout << endl;
}
int main()
{
vector< int > v {4, 1, 3, 5, 2, 3, 1, 7};
printVector(v);
// below snippet find first number greater than 4
// find_if searches for an element for which
// function(third argument) returns true
vector< int >:: iterator p = find_if(v.begin(), v.end(), []( int i)
{
return i > 4;
});
cout << "First number greater than 4 is : " << *p << endl;
// function to sort vector, lambda expression is for sorting in
// non-increasing order Compiler can make out return type as
// bool, but shown here just for explanation
sort(v.begin(), v.end(), []( const int & a, const int & b) -> bool
{
return a > b;
});
printVector(v);
// function to count numbers greater than or equal to 5
int count_5 = count_if(v.begin(), v.end(), []( int a)
{
return (a >= 5);
});
cout << "The number of elements greater than or equal to 5 is : "
<< count_5 << endl;
// function for removing duplicate element (after sorting all
// duplicate comes together)
p = unique(v.begin(), v.end(), []( int a, int b)
{
return a == b;
});
// resizing vector to make size equal to total different number
v.resize(distance(v.begin(), p));
printVector(v);
// accumulate function accumulate the container on the basis of
// function provided as third argument
int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int f = accumulate(arr, arr + 10, 1, []( int i, int j)
{
return i * j;
});
cout << "Factorial of 10 is : " << f << endl;
//     We can also access function by storing this into variable
auto square = []( int i)
{
return i * i;
};
cout << "Square of 5 is : " << square(5) << endl;
}


输出:

4 1 3 5 2 3 1 7 First number greater than 4 is : 57 5 4 3 3 2 1 1 The number of elements greater than or equal to 5 is : 27 5 4 3 2 1 Factorial of 10 is : 3628800Square of 5 is : 25

通过从封闭范围访问变量,lambda表达式可以比普通函数更强大。我们可以通过三种方式从封闭范围中捕获外部变量: 通过引用捕获 按价值捕获 两者捕获(混合捕获) 用于捕获变量的语法: [&]:通过引用捕获所有外部变量 [=]:按值捕获所有外部变量 [a和b]:按值捕获a,按引用捕获b 带有空capture子句[]的lambda只能访问其本地变量。 捕获方式如下所示:

CPP

// C++ program to demonstrate lambda expression in C++
#include <bits/stdc++.h>
using namespace std;
int main()
{
vector< int > v1 = {3, 1, 7, 9};
vector< int > v2 = {10, 2, 7, 16, 9};
//  access v1 and v2 by reference
auto pushinto = [&] ( int m)
{
v1.push_back(m);
v2.push_back(m);
};
// it pushes 20 in both v1 and v2
pushinto(20);
// access v1 by copy
[v1]()
{
for ( auto p = v1.begin(); p != v1.end(); p++)
{
cout << *p << " " ;
}
};
int N = 5;
// below snippet find first number greater than N
// [N]  denotes,   can access only N by value
vector< int >:: iterator p = find_if(v1.begin(), v1.end(), [N]( int i)
{
return i > N;
});
cout << "First number greater than 5 is : " << *p << endl;
// function to count numbers greater than or equal to N
// [=] denotes,   can access all variable
int count_N = count_if(v1.begin(), v1.end(), [=]( int a)
{
return (a >= N);
});
cout << "The number of elements greater than or equal to 5 is : "
<< count_N << endl;
}


输出:

First number greater than 5 is : 7The number of elements greater than or equal to 5 is : 3

lambda表达式只能在C++ 11和版本之后工作。 本文由Utkarsh Trivedi撰稿。如果您发现任何不正确的地方,或者您想分享有关上述主题的更多信息,请写评论

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