一阶逻辑(FOL)语句((R)∨ Q)∧ (P∨ Q)等同于以下哪项? (A) ((R)∨ (Q)∧ (P∨ (Q)∧ (R)∨ P) ) (B) ((R)∨ Q)∧ (P∨ (Q)∧ (R)∨ P) ) (C) ((R)∨ Q)∧ (P∨ (Q)∧ (R)∨ (-P)) (D) ((R)∨ Q)∧ (P∨ (Q)∧ (-R)∨ P) ) 答复: (B) 说明: 一阶逻辑(FOL)语句((R)∨ Q)∧ (P∨ Q)等于PR+,QR+PQ等于:
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Option 1- ((R ∨ ¬Q) ∧ (P ∨ ¬Q) ∧ (R ∨ P)) is (R + ¬Q)(P + ¬Q)(R + P)) i.e. = RP + R¬Q +P¬Q not equivalent to PR + ¬QR + PQ . 2- ((R ∨ Q) ∧ (P ∨ ¬Q) ∧ (R ∨ P)) is (R + Q)(P + ¬Q)(P + R) i.e. = PR + ¬QR + PQ is exactly same. 3- ((R ∨ Q) ∧ (P ∨ ¬Q) ∧ (R ∨ ¬P)) is (R + Q)(P + ¬Q)(R + ¬P) i.e. = PR + ¬QR + R(P ↔ Q) not equivalent to PR + ¬QR + PQ . 4- ((R ∨ Q) ∧ (P ∨ ¬Q) ∧ ( ¬R ∨ P)) is (R + Q)(P + ¬Q)(¬R + P) i.e. = PR + PQ + P(Q → R) not equivalent to PR + ¬QR + PQ.
因此,选项(B)是正确的。
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