鉴于 N 持续时间以 男:SS ,其中MM表示分钟,SS表示秒。任务是以 HH:MM:SS . 例如:
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Input : n = 5 duration1 = 0 : 45 duration1 = 2 : 31 duration1 = 3 : 11 duration1 = 2 : 27 duration1 = 1 : 28Output : 0 : 10 : 22Initially, sum = 0On adding duration 1, sum = 0 hour 0 minutes 45 seconds.On adding duration 2, sum = 0 hour 3 minutes 16 seconds.On adding duration 3, sum = 0 hour 6 minutes 27 seconds.On adding duration 4, sum = 0 hour 8 minutes 54 seconds.On adding duration 5, sum = 0 hour 10 minutes 22 seconds
其想法是将所有给定的持续时间转换为秒。一旦我们知道以秒为单位的持续时间,我们就可以计算以秒为单位的持续时间之和。 为了得到小时数,我们必须将总持续时间(以秒为单位)除以3600。余数用于计算分钟数和秒数。通过将余数除以60,我们得到分钟数,余数就是秒数。 以下是该方法的实施情况:
C++
// CPP Program to find the sum of all duration // in the form of MM : SS. #include <bits/stdc++.h> using namespace std; // Print sum of all duration. void printSum( int m[], int s[], int n) { int total = 0; // finding total seconds for ( int i = 0; i < n; i++) { total += s[i]; total += (m[i] * 60); } // print the hours. cout << total / 3600 << " : " ; total %= 3600; // print the minutes. cout << total / 60 << ": " ; total %= 60; // print the hours. cout << total << endl; } // Driven Program int main() { int m[] = { 0, 2, 3, 2, 1 }; int s[] = { 45, 31, 11, 27, 28 }; int n = sizeof (m)/ sizeof (m[0]); printSum(m, s, n); return 0; } |
JAVA
// Java Program to find the // sum of all duration in // the form of MM : SS. class GFG { // Print sum of all duration. static void printSum( int m[], int s[], int n) { int total = 0 ; // finding total seconds for ( int i = 0 ; i < n; i++) { total += s[i]; total += (m[i] * 60 ); } // print the hours. System.out.print(total / 3600 + " : " ); total %= 3600 ; // print the minutes. System.out.print(total / 60 + ": " ); total %= 60 ; // print the hours. System.out.println(total); } // Driver code public static void main (String[] args) { int m[] = { 0 , 2 , 3 , 2 , 1 }; int s[] = { 45 , 31 , 11 , 27 , 28 }; int n = m.length; printSum(m, s, n); } } // This code is contributed by Anant Agarwal. |
Python3
# Python3 code to find the sum of # all duration in the form of MM : SS. # Print sum of all duration. def printSum (m, s, n ): total = 0 # finding total seconds for i in range (n): total + = s[i] total + = (m[i] * 60 ) # print the hours. print ( int (total / 3600 ) , end = " : " ) total % = 3600 # print the minutes. print ( int (total / 60 ) , end = ": " ) total % = 60 # print the hours. print ( int (total)) # Driven Code m = [ 0 , 2 , 3 , 2 , 1 ] s = [ 45 , 31 , 11 , 27 , 28 ] n = len (m) printSum(m, s, n) # This code is contributed by "Sharad_Bhardwaj". |
C#
// C# Program to find the // sum of all duration in // the form of MM : SS. using System; class GFG { // Print sum of all duration. static void printSum( int []m, int []s, int n) { int total = 0; // finding total seconds for ( int i = 0; i < n; i++) { total += s[i]; total += (m[i] * 60); } // print the hours. Console.Write(total / 3600 + " : " ); total %= 3600; // print the minutes. Console.Write(total / 60 + ": " ); total %= 60; // print the hours. Console.Write(total); } // Driver code public static void Main () { int []m = {0, 2, 3, 2, 1 }; int []s = { 45, 31, 11, 27, 28 }; int n = m.Length; printSum(m, s, n); } } // This code is contributed by vt_m. |
PHP
<?php // PHP Program to find the // sum of all duration // in the form of MM : SS. // Print sum of all duration. function printSum( $m , $s , $n ) { $total = 0; // finding total seconds for ( $i = 0; $i < $n ; $i ++) { $total += $s [ $i ]; $total += ( $m [ $i ] * 60); } // print the hours. echo floor ( $total / 3600) , " : " ; $total %= 3600; // print the minutes. echo floor ( $total / 60) , ": " ; $total %= 60; // print the hours. echo floor ( $total ) ; } // Driver Code $m = array (0, 2, 3, 2, 1); $s = array (45, 31, 11, 27, 28); $n = count ( $m ); printSum( $m , $s , $n ); // This code is contributed by anuj_67. ?> |
Javascript
<script> // javascript Program to find the // sum of all duration in // the form of MM : SS. // Print sum of all duration. function printSum(m, s, n) { var total = 0; // finding total seconds for ( var i = 0; i < n; i++) { total += s[i]; total += (m[i] * 60); } // print the hours. document.write((total / 3600).toFixed(0) + " : " ); total %= 3600; // print the minutes. document.write((total / 60).toFixed(0) + ": " ); total %= 60; // print the hours. document.write(total); } // Driver code var m = [0, 2, 3, 2, 1 ]; var s = [45, 31, 11, 27, 28 ]; var n = m.length; printSum(m, s, n); // This code is contributed by bunnyram19 </script> |
输出:
0 : 10: 22
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